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Easy Math Problem (?)

 
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redslothx
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PostPosted: Sat Aug 29, 2009 3:25 pm    Post subject: Easy Math Problem (?) Reply with quote

I'm helping someone do their homework, and i ran into a problem that doesn't make any sense >_>


Here it is.

g(x) = x^2+2x+3

[g(x+5)]


assuming i remember this correctly, it should be:

g(x+5) = (x+5)^2 + 2(x+5) + 3
g(x+5) = X^2 + 25 + 2x + 10 + 3
g(x+5) = X^2 + 2x + 38



According to the answers in the book, the answer should be:
x^2 + 12x + 38


I don't see where this 12x came from >_>

Help?

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AverageAzn247
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PostPosted: Sat Aug 29, 2009 3:39 pm    Post subject: Re: Easy Math Problem (?) Reply with quote

Ozymandias wrote:
I'm helping someone do their homework, and i ran into a problem that doesn't make any sense >_>


Here it is.

g(x) = x^2+2x+3

[g(x+5)]


assuming i remember this correctly, it should be:

g(x+5) = (x+5)^2 + 2(x+5) + 3
g(x+5) = X^2 + 25 + 2x + 10 + 3
g(x+5) = X^2 + 2x + 38



According to the answers in the book, the answer should be:
x^2 + 12x + 38


I don't see where this 12x came from >_>

Help?
u foiled wrong. (x+5)^2 =/= x^2+25. It should be x^2+10x+25
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redslothx
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Reputation: 13

Joined: 27 Nov 2006
Posts: 1949

PostPosted: Sat Aug 29, 2009 3:43 pm    Post subject: Re: Easy Math Problem (?) Reply with quote

AverageAzn247 wrote:
Ozymandias wrote:
I'm helping someone do their homework, and i ran into a problem that doesn't make any sense >_>


Here it is.

g(x) = x^2+2x+3

[g(x+5)]


assuming i remember this correctly, it should be:

g(x+5) = (x+5)^2 + 2(x+5) + 3
g(x+5) = X^2 + 25 + 2x + 10 + 3
g(x+5) = X^2 + 2x + 38



According to the answers in the book, the answer should be:
x^2 + 12x + 38


I don't see where this 12x came from >_>

Help?
u foiled wrong. (x+5)^2 =/= x^2+25. It should be x^2+10x+25



(Confused)
Did you just get three different values from (X+5)^2
?

---------
the final answer at the back of the book said it was: X^2 + 12x + 38

so it can't be: X^2 + 10x + 25
(if that's what you meant)

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AverageAzn247
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PostPosted: Sat Aug 29, 2009 3:46 pm    Post subject: Re: Easy Math Problem (?) Reply with quote

Ozymandias wrote:
AverageAzn247 wrote:
Ozymandias wrote:
I'm helping someone do their homework, and i ran into a problem that doesn't make any sense >_>


Here it is.

g(x) = x^2+2x+3

[g(x+5)]


assuming i remember this correctly, it should be:

g(x+5) = (x+5)^2 + 2(x+5) + 3
g(x+5) = X^2 + 25 + 2x + 10 + 3
g(x+5) = X^2 + 2x + 38



According to the answers in the book, the answer should be:
x^2 + 12x + 38


I don't see where this 12x came from >_>

Help?
u foiled wrong. (x+5)^2 =/= x^2+25. It should be x^2+10x+25


how can you get three different values from (X+5)^2

? O_O

---------
the final answer at the back of the book said it was (X^2 + 12x + 3Cool

so it can't be: X^2 + 10x + 25
(if that's what you meant)
when u square(X+5)^2 caz (x+5)(x+5)
x^2+5x+5x+25. And the book answer is rite. I just pointed out the step u made a mistake in. The final part is x^2+5x+5x+25+2x + 10 + 3
=x^2 + 12x + 38

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redslothx
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Reputation: 13

Joined: 27 Nov 2006
Posts: 1949

PostPosted: Sat Aug 29, 2009 3:47 pm    Post subject: Re: Easy Math Problem (?) Reply with quote

AverageAzn247 wrote:
Ozymandias wrote:
AverageAzn247 wrote:
Ozymandias wrote:
I'm helping someone do their homework, and i ran into a problem that doesn't make any sense >_>


Here it is.

g(x) = x^2+2x+3

[g(x+5)]


assuming i remember this correctly, it should be:

g(x+5) = (x+5)^2 + 2(x+5) + 3
g(x+5) = X^2 + 25 + 2x + 10 + 3
g(x+5) = X^2 + 2x + 38



According to the answers in the book, the answer should be:
x^2 + 12x + 38


I don't see where this 12x came from >_>

Help?
u foiled wrong. (x+5)^2 =/= x^2+25. It should be x^2+10x+25


how can you get three different values from (X+5)^2

? O_O

---------
the final answer at the back of the book said it was (X^2 + 12x + 3Cool

so it can't be: X^2 + 10x + 25
(if that's what you meant)
when u square(X+5)^2 caz (x+5)(x+5)
x^2+5x+5x+25. And the book answer is rite. I just pointed out the step u made a mistake in. The final part is x^2+5x+5x+25+2x + 10 + 3
=x^2 + 12x + 38


Oh...

thanks xD

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