Posted: Tue Jun 16, 2009 12:31 am Post subject: How do I find the limit of a Geometric progression?
Consider the square puzzle below. The large outer square has a side length of 2 metres. The midpoints of the adjacent sides are joined to form a smaller square. The midpoints of the adjacent sides of that square are joined to form a smaller square and so on.
Investigate and evaluate the validity of the argument that if this pattern is continued for ever the sum of the perimetres of all the squares will approach a definite limit.
Now, using Pythagoras I have already been able to calculate that the perimetre goes.
8, 4√2, 4, (4√2)/2...
With the first term (a) being 8 and the common ratio (r) being √0.5
After using the formula for sum to infinity (S=a/1-r) I was able to calculate that its sum to infinity is 6.828, but is that the limit that I am looking for? And can somebody point me in the right direction. _________________
You cannot post new topics in this forum You cannot reply to topics in this forum You cannot edit your posts in this forum You cannot delete your posts in this forum You cannot vote in polls in this forum You cannot attach files in this forum You can download files in this forum