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How do I find the limit of a Geometric progression?

 
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Trucido
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PostPosted: Tue Jun 16, 2009 12:31 am    Post subject: How do I find the limit of a Geometric progression? Reply with quote

Consider the square puzzle below. The large outer square has a side length of 2 metres. The midpoints of the adjacent sides are joined to form a smaller square. The midpoints of the adjacent sides of that square are joined to form a smaller square and so on.

Investigate and evaluate the validity of the argument that if this pattern is continued for ever the sum of the perimetres of all the squares will approach a definite limit.



Now, using Pythagoras I have already been able to calculate that the perimetre goes.
8, 4√2, 4, (4√2)/2...

With the first term (a) being 8 and the common ratio (r) being √0.5

After using the formula for sum to infinity (S=a/1-r) I was able to calculate that its sum to infinity is 6.828, but is that the limit that I am looking for? And can somebody point me in the right direction.

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GARCIE
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PostPosted: Tue Jun 16, 2009 1:17 am    Post subject: Reply with quote

wat grade math is this
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Trucido
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PostPosted: Tue Jun 16, 2009 1:27 am    Post subject: Reply with quote

GENTLEMEN wrote:
wat grade math is this

Here in Australia I'm doing this in grade 11 maths c.
So second last year of highschool, and the 'hardest' maths my school offers.

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Trucido
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PostPosted: Tue Jun 16, 2009 6:46 am    Post subject: Reply with quote

Never mind this, I had the sequence wrong, and all I needed to do was multiply the sum to infinity by 4.
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