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Correct way for address pointers and offsets

 
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Bit Byte
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PostPosted: Sat Jul 29, 2023 4:40 am    Post subject: Correct way for address pointers and offsets Reply with quote
I have this c#:

Code:
Entity= Memory.GetPointerAddress64Bit(ModuleBase + 0x1CBBA78, new int[] { 0x308, 0x8, 0 }, 3);


In CE script I can write same thing:
Code:
local Entity = readInteger('[[[game.exe+1CBBA78]+308]+8]+0')

Now using from above I have c#:
Code:
EnemyHp = Memory.GetPointerAddress64Bit(Entity+ 0x1a8, new int[] { 0x28 }, 1);


My question which one or any other correct way to write in CE Script:

Code:
local EnemyHp = readInteger('[[[[[game.exe+1CBBA78]+308]+8]+0]+1A8]+28')


or

Code:
local EnemyHp = readInteger('[[Entity]+1A8]+28')


or

Code:
local EnemyHp = readInteger('[Entity+1A8]+28')
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LeFiXER
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PostPosted: Sat Jul 29, 2023 6:54 am    Post subject: Reply with quote
I would use getAddress():
Code:

local Entity = getAddress('[[[game.exe+1CBBA78]+308]+8]+0')
local EnemyHP = getAddress('[[' .. Entity .. ']+1A8]+28')


Perhaps there are other ways. But I like this method; I find it makes for easier reading.
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Bit Byte
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PostPosted: Sat Jul 29, 2023 7:38 am    Post subject: Reply with quote
Would both these return the same value?:

Code:
local EnemyHP = getAddress('[[Entity]+1A8]+28')

Code:
local EnemyHp = getAddress('[[[[[game.exe+1CBBA78]+308]+8]+0]+1A8]+28')



How might I see in console?
Also would creating a pointer like this work?

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Pointer.JPG
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LeFiXER
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PostPosted: Sat Jul 29, 2023 9:10 am    Post subject: Reply with quote
If 'Entity' was a registered symbol to a valid address then yes, otherwise no.

Use print:
Code:

local EnemyHp = getAddress('[[[[[game.exe+1CBBA78]+308]+8]+0]+1A8]+28')
print(string.format('%X', EnemyHp))
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ParkourPenguin
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PostPosted: Sat Jul 29, 2023 11:21 am    Post subject: This post has 1 review(s) Reply with quote
a2z wrote:
readInteger('[Entity+1A8]+28')
The argument you're passing to readInteger is a string. Writing a variable name in a string isn't going to do anything magical. It's just going to be a string with a variable name in it.
Code:
local foo = 5
print('foo')  -- prints `foo`
print(foo)    -- prints `5`

LeFiXER wrote:
Code:
local EnemyHP = getAddress('[[' .. Entity .. ']+1A8]+28')
`Entity` is an integer. The string concatenation operation `..` converts integers to their decimal string representation. CE assumes it should be hexadecimal.

I'm going to answer the first post based on this pointer path being valid:
Code:
local EnemyHp = readInteger('[[[[[game.exe+1CBBA78]+308]+8]+0]+1A8]+28')
Also:
a2z wrote:
Code:
local Entity = readInteger('[[[game.exe+1CBBA78]+308]+8]+0')
`Entity` is a node in the pointer path. It should really be readPointer not readInteger.

You could use string.format:
Code:
local EnemyHp = readInteger(('[%X+1A8]+28'):format(Entity))
But converting to a string just so CE can convert it back to an integer is a little weird.
readPointer would be more appropriate but perhaps less ergonomic the more offsets you have:
Code:
local EnemyHp = readInteger(readPointer(Entity+0x1A8)+0x28)


If you're doing this often, maybe write a helper function:
Code:
function traversePointerPath(baseAddress, offsets)
  local node = baseAddress
  for _,o in ipairs(offsets) do
    node = readPointer(node) + o
  end
  return node
end

-- NB: in the pointer path `[game.exe+1234]+3C`, the base address is _not_ `game.exe` and
-- the first offset is _not_ 0x1234: they're `game.exe+1234` and 0xC3 respectively
-- similar story here
local EnemyHP = readInteger(traversePointerPath(Entity+0x1A8, {0x28}))

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LeFiXER
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PostPosted: Sat Jul 29, 2023 3:01 pm    Post subject: Reply with quote
ParkourPenguin wrote:

LeFiXER wrote:
Code:
local EnemyHP = getAddress('[[' .. Entity .. ']+1A8]+28')
`Entity` is an integer. The string concatenation operation `..` converts integers to their decimal string representation. CE assumes it should be hexadecimal.


Makes sense since I format the address as a hex string anyway. Either way, it's good to know. Thanks for the tip! It's highly appreciated.
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Bit Byte
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PostPosted: Sun Jul 30, 2023 5:41 am    Post subject: Reply with quote
Thank you guys for the help.
Why is EnemyHp1 & EnemyHp2 having 2 different outputs:

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test.JPG
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LeFiXER
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PostPosted: Sun Jul 30, 2023 1:04 pm    Post subject: Reply with quote
Because EnemyHp2 is adding offsets to the address rather than adding to the address value held at the address.
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Bit Byte
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PostPosted: Mon Jul 31, 2023 5:14 am    Post subject: Reply with quote
LeFiXER wrote:
Because EnemyHp2 is adding offsets to the address rather than adding to the address value held at the address.


Ok, what is being done here:
Code:
Entity = Memory.GetPointerAddress64Bit(ModuleBase + 0x1CBBA78, new int[] { 0x308, 0x8, 0 }, 3);


Code:
IntPtr EnemyHp = Memory.GetPointerAddress64Bit(Entity + 0x1a8, new int[] { 0x28 }, 1);


Is EnemyHp adding offsets to the address or address value held at the address?
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LeFiXER
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PostPosted: Mon Jul 31, 2023 9:10 am    Post subject: Reply with quote
I'm unfamiliar with C# and the functions used by the Memory module so cannot explain exactly what's happening. Although from a glance it appears to take several arguments as described here:
Code:

Memory.GetPointerAddress64Bit(address, array_of_offsets, offset_count)

Which then would loop through the array adding the offset to each value returned by the function.
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