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[Solved] AA: How to multiply x1.7 with integer result?

 
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Xenocritus
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Joined: 27 Dec 2020
Posts: 23

PostPosted: Wed Feb 17, 2021 2:33 am    Post subject: [Solved] AA: How to multiply x1.7 with integer result? Reply with quote

Hi,

I want to adjust/balance some game aspects and decided for example, x1.7 is a good multiplier for a specific variable. And I want to do it in auto assembler script.

My value EAX is 4 bytes Integer, and multipliying x1.7 is always 4 bytes number, but I don't know how to multiply x1.7 nor how to round the result.

So, in pseudocode I wanted some like:

EAX = floor(EAX * 1.7)

Note: The round can be whatever, truncate, floor, ceil, near...

Thanks!


Last edited by Xenocritus on Wed Feb 17, 2021 1:51 pm; edited 1 time in total
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Dark Byte
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Joined: 09 May 2003
Posts: 23325
Location: The netherlands

PostPosted: Wed Feb 17, 2021 3:17 am    Post subject: Reply with quote

multiply by 17 followed by divide by 10

Code:

push edx
push ecx
mov ecx,#17
mul ecx //multiply eax with ecx and store the result in eax:edx
mov ecx,#10
xor edx,edx
div ecx //divide eax:edx by 10 and store the result in eax

pop ecx
pop edx


next version you can do
Code:

{$ccode value=EAX}
*value=*value*1.7;
{$asm}

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Xenocritus
Newbie cheater
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Joined: 27 Dec 2020
Posts: 23

PostPosted: Wed Feb 17, 2021 1:51 pm    Post subject: Reply with quote

Many thanks!!

I learned a lot with that respone lol.
- Now I know I can use Push/Pop instead of creating a variable to backup my values, lol Smile
- I assume xor edx, edx is just an alternative to mov edx, 0.

[solved]
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