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Cheat engine tutorial step 9 help!

 
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hamad12a
How do I cheat?
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Joined: 21 Mar 2020
Posts: 1

PostPosted: Sat Mar 21, 2020 4:33 pm    Post subject: Cheat engine tutorial step 9 help! Reply with quote

I followed the answer to step 9 in cheat engine tutorial on youtube,

however, I want to use different offset other than 14, say for e.g., the case which includes two offsets, offset 0: 60 ; offset 1: 1B0.
My question is how to include that in the script? using

Code:
cmp [rbx+"?"],?
je short exit

[/url]
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DanyDollaro
Master Cheater
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Joined: 01 Aug 2019
Posts: 303

PostPosted: Sun Mar 22, 2020 3:31 am    Post subject: Reply with quote

You have to use a register so you can load the pointers up to the value you want, the implementation would be this:
Code:
push rbx // Save the value of rbx on the stack

mov rbx, [rbx + Offset_0]
mov rbx, [rbx + Offset_1]
cmp rbx, The_Value_You_Want

je short exit
...

exit:
pop rbx // Restore the value of rbx
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xTnsv
Newbie cheater
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Joined: 25 Mar 2020
Posts: 10
Location: Philadelphia

PostPosted: Sat Apr 04, 2020 7:00 pm    Post subject: Reply with quote

You really only need offset 04 and 10 which is HP and Team.

Code:

newmem:
  cmp [ebx+10],1
  je originalcode
  mov [ebx+04],0
  jmp originalcode


Very basic here: [ebx+10] holds the team value (1 for friend, 2 for enemy).
So if it's a friendly it jumps to the original code and we take a normal hit.
If it's an enemy (not equal to 1) it will move a 0 into the value stored at [ebx+04] which holds the HP and leaves the enemy dead.
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