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Corroder
Grandmaster Cheater Supreme
 Reputation: 75
Joined: 10 Apr 2015
Posts: 1668
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 Posted: Mon Apr 29, 2019 1:23 am Post subject: Get Data Base To Table Name |
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Hi there,
How this should be work.
table1 = {1,2,3}
table2 = {4,5,6}
level = 1
I can't use / not work:
| Code: | if level == 1 then
tbl = table1
else
tbl = table2
end |
With a helper function:
| Code: | local function getTableName(tbl)
for k, v in pairs(_G) do
if v == tbl then
return k
end
end
return nil
end
tbl = getTableName(table1)
if tbl == 'table1' then
--- assign a current table to table1
--- get data from table1
--- do some kinds of stuff
else
--- assign a current table to table2
--- get data from table2
--- do some kinds of stuff
end
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With helper function, it should work but I think that not effective.
How to assign tbl = [assigned table] should work?
Regards,
_________________
Stealing Code From Stolen Code...
And Admit It.. Hmmm....Typically LOL |
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atom0s
Moderator
 Reputation: 205
Joined: 25 Jan 2006
Posts: 8587
Location: 127.0.0.1
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| Posted: Wed May 01, 2019 9:14 pm Post subject: |
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Personally, I think you should probably go about this in a different manner.
While you can get the variable names different ways, it comes with the hit of performance, especially when it requires the use to the 'debug' library that Lua comes with. Since that kind of stuff is meant only for debugging code and finding problems, it shouldn't be used in real-world code unless specifically required.
This is the kind of thing that can be resolved approaching the problem a different way instead.
You can pass a more defined object that contains both the name of the object and the data itself, which would probably be better suited for this. For example, something like this:
| Code: | table1 = {
name = 'table1',
data = { 1, 2, 3 }
};
table2 = {
name = 'table2',
data = { 3, 4, 5 }
}; |
Then you can access the name as it will always be tied to the object.
Based on your code above as well you can then setup things like:
| Code: | levels = {
[1] = table1,
[2] = table2,
};
if (level == 1) then
tbl = levels[1];
else
tbl = levels[2];
end
|
Assuming you stick with a proper indexed table for levels too, you can just replace the if/then block with direct indexing or table lookups. You can also build out the levels table to include an id for the level and attach the data table to that, then use a helper function to do a simple lookup to get a level entry.
| Code: |
levels = {
{ id = 1, level = table1 },
{ id = 2, level = table2 },
};
local function getLevel(id)
for _, v in pairs(levels) do
if (v.id == id) then
return v.level;
end
end
return nil;
end
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Corroder
Grandmaster Cheater Supreme
Reputation: 75
Joined: 10 Apr 2015
Posts: 1668
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| Posted: Fri May 03, 2019 8:45 am Post subject: |
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Nah, atom0s thank so much for details explanation and I clearly understand. Great...
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Stealing Code From Stolen Code...
And Admit It.. Hmmm....Typically LOL |
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