Cheat Engine

[Clasmir]

It has been since 1985 that I touched assembler and that was with a z80 processor. I don't remember any of it.

I have this from an AI Wars script that I want to understand (I want to adjust the knowledge to a smaller value):

cmp dword ptr [playerstatsresourcesset_enable], #0
je playerstatsresourcesset_exit
mov [eax+288], #1578106880
mov [eax+28c], #95
mov [eax+29c], #1000000
playerstatsresourcesset_exit:

I want to verify what I understand and don't understand lol.

Take: mov [eax+288], #1578106880

The [eax+288] does that mean treat the final address as a pointer?

What does the # mean?

Am I taking the value 1578106880 and placing that big number into the address of the pointer final location [eax+288] ?


I know this is going to piss of the die-hards. I looked for tutorials and references. I found this www intel com/content/www/us/en/architecture-and-technology/64-ia-32-architectures-software-developer-vol-2a-manual html but it hurts my head. 600+ pages. Ugh.

If you feel like helping yet another schmuck. Thanks.

[Dark Byte]

[eax+288] means take the value in eax, add 0x288 to it, and interpret that new value as an address

mov will place the second parameters value inside the first parameters. in this case it will write that value to the address eax+288 represents

that manual is good. i use it as well. Don't bother reading it all, just look up what you need

[Clasmir]

Thank you.

Does the # signify a decimal number versus hex?

I checked the MOV portion of that PDF. I guess I'll need to understand more before even that section makes sense.

Thanks again.

[Dark Byte]

# means integer yes. an alternate notation is (int)
the first few chapters describe parameters.