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gogodr I post too much
Reputation: 125
Joined: 19 Dec 2006 Posts: 2041
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Posted: Tue Aug 14, 2012 7:27 pm Post subject: Ignore this please |
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Tecincas inferenciales:
-estimacion de parametros
-prueba de hipotesis
Distribuciones:
Normal - N
ji^2 - X(n)^2
t - t(n)
Fisher - F
N::
Dominio = Reales
Maximo x en moda
simetrico
suma de dos normales es otra normal
X1~n(5;2^2)
X2~n(20;5^2)
(x1+x2)~n(25,29)
(x1-x2)~n(-5,29)
a) P(x<4) = 0.2266
b) P(x>10) = 0.2266
c) P(5<x< = 0.2902
d) a tal que P(x<a) = 0.9 , a = 12.13
e) a tal que P(x>=a)=0.6 , a = 5.9877
f) a y b tal que P(x<a)= 0.01 y P(a<=x<=b)=0.98 , a= -2.305 b=16.31
g) a y b tal que P(x>b)= 0.03 y P(a<=x<=b)=0.9 , a= 1.097 b=14.52
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X~n(µ;5^2) y P(x< =0.3
a) µ ?
P( (x-µ)/σ < (8-µ)/5 ) = 0.3
P(Z<(8-µ)/5) = 0.3
-0.5244 = (8-µ)/5
µ = 10.62
b) P(x>12) = 0.3913
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X:Tiempo de vide del escape
X~n(3;0.5^2) = 0.02275
C = Costo total del remplazo
Y: numero de escapes con fallas para reparar
C = 10*Y
E(c)= E(10Y) = 10*E(Y) = 10(500000) * 0.02275 = 113750 |
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trebor Grandmaster Cheater
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Joined: 23 Dec 2007 Posts: 816
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Posted: Tue Aug 14, 2012 7:29 pm Post subject: |
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| huehuehuehuehuehue |
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Up2Admin I'm a spammer
Reputation: 126
Joined: 17 Oct 2007 Posts: 6548 Location: Texas
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Posted: Tue Aug 14, 2012 7:38 pm Post subject: |
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jajajajajajajajajajaja _________________
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Cryoma Member of the Year
Reputation: 198
Joined: 14 Jan 2009 Posts: 1819
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Posted: Tue Aug 14, 2012 7:56 pm Post subject: |
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| could you imagine if you looked at your math homework and there were a bunch of smug sunglasses smileys? |
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