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A_jj74
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 Posted: Sun Mar 07, 2010 3:15 pm Post subject: [C++] Circle. |
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How would I get the Degree of the Circle at the point where the line (x1,y1,x2,y2) intersects the circle programatically?
Heres an Image:
I know its 225 but I want to do it Programatically.
Thanks in advance.
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Deltron Z
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| Posted: Sun Mar 07, 2010 3:44 pm Post subject: |
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You drawed your circle wrong, 360 is one round + 0 degrees, it should have been:
12:00 O'clock = 0 degrees.
03:00 O'clock = 90 degrees.
06:00 O'clock = 180 degrees.
09:00 O'clock = 270 degrees.
Anyway, you can easily do this with trigonometry:
X = R * sin D
Y = R * cos D
(R = Radius, D = Degrees)
With 0 degrees being in the same place as in your draw, simply decrease 90 from degrees before you calculate the location. just use your head.
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A_jj74
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Joined: 14 Nov 2009
Posts: 41
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| Posted: Sun Mar 07, 2010 5:18 pm Post subject: |
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Ooops lol!
Ok I've got that with the Trigonometry.
But what do you mean with:
| Quote: | | With 0 degrees being in the same place as in your draw, simply decrease 90 from degrees before you calculate the location. just use your head. |
I want my Cursor to start moving from the line (CPX,CPY,X,Y)
(In the image it was x1,y1,x2,y2)
CPX is the Current X pos.
CPY is the Current Y pos.
X is the x pos of the center point of the Circle.
Y is the y pos of the center point of the Circle.
My code so far:
| Code: | #include <iostream>
#include <windows.h>
#include <math.h>
using namespace std;
void Circle(int CPX, int CPY, int X, int Y, int rad)
{
//CPX and CPY arent implemented yet
float deg = 0;
int dx = X;
int dy = Y;
float maxdeg = 6.4+deg; //+ deg to make it a full circle, if the cursor starts at a higher degree than 0
Sleep(5);
do
{
X = round(rad * cos(deg));
Y = round(rad * sin(deg));
SetCursorPos(X+dx, Y+dy);
deg += 0.01;
Sleep(2);
}
while (deg <= maxdeg);
}
int main()
{
Circle(100,100,200,200,100);
return 0;
} |
Thanks.
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Odecey
Master Cheater
 Reputation: 1
Joined: 19 Apr 2007
Posts: 259
Location: Scandinavia
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| Posted: Mon Mar 08, 2010 1:31 am Post subject: |
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I use Atan2 to calculate this. | Code: | | double angle = Atan2(x2-x1,y2-y2); |
I'm a little unsure what you are asking in your second post though. Do you want the cursor to move in a circular pattern? If so, I made a function which calculates the points along a circular trajectory which you can use: | Code: |
// It's worth noting that this is coded in C#, so there might be some diffrences in syntax.
public void Step(int step)
{
CurrentVelocity = StartVelocity + Acceleration * step;// These are doubles
Length = 0.5 * (StartVelocity + CurrentVelocity) * step;
_angBuff = Length / _lenToAng;// _lenToAng is the result of Circumference / (2*pi)
CurrentPosition = Center + (_clockwise ? Vector.GetVectorByLengthAndAngle(_radius, _angBuff + (StartPosition - Center).GetAngle()) : Vector.GetVectorByLengthAndAngle(_radius, (StartPosition - Center).GetAngle()- _angBuff ));// CurrentPosition, StartPosition and Center are 2D vector objects(My own custom class). _radius is double. _clockwise is bool.
}
public static Vector GetVectorByLengthAndAngle(double length, double angle)
{
length = Math.Abs(length);
return new Vector(length * Math.Cos(angle), length * Math.Sin(angle));
} |
If there is something in the code you don't understand, don't hesitate to ask!
_________________
Never confuse activity with productivity. You can be busy without a purpose, but what's the point?- Rick Warren |
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Flyte
Peanuts!!!!
 Reputation: 6
Joined: 19 Apr 2006
Posts: 1887
Location: Canada
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| Posted: Mon Mar 08, 2010 2:27 am Post subject: |
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| Deltron Z wrote: | 12:00 O'clock = π/2 radians, 90 degrees.
03:00 O'clock = 0 radians, 0 degrees.
06:00 O'clock = 3π/2 radians, 270 degrees.
09:00 O'clock = π radians, 180 degrees. |
FTFY, YW.
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A_jj74
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Joined: 14 Nov 2009
Posts: 41
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| Posted: Mon Mar 08, 2010 2:46 am Post subject: |
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Odecey thanks for your reply but C# doesn't help me a lot =/.
Basically I need to set the "Starting Degree" (where the mouse should start to move from) to that, I don't know how to explain it.
PS: It should move the Cursor "along" the Imaginary Circle (the Circle with the Black Perimeter), just wrote this, not that you think it should move the Cursor around the Black Circle with a +Distance.
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Flyte
Peanuts!!!!
Reputation: 6
Joined: 19 Apr 2006
Posts: 1887
Location: Canada
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| Posted: Mon Mar 08, 2010 4:04 am Post subject: |
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Most I could be bothered to write. You might want to use a vector math library to make it cleaner.
| Code: | // MoveMouseInCircle.cpp : Defines the entry point for the console application.
//
#include <Windows.h>
#include <cmath>
#include <utility>
using namespace std;
struct Point {
double X;
double Y;
Point()
: X(0), Y(0) {}
Point(double x, double y)
: X(x), Y(y) {}
};
class GenerateCircleCoOrds {
double const radius_;
double currentAngle_;
public:
GenerateCircleCoOrds(double x, double y)
: radius_(::sqrt(::pow(x, 2) + ::pow(y, 2))),
currentAngle_(::atan2(x, y)) {}
Point Step(double dPhi) {
currentAngle_ += dPhi;
return Point(radius_ * ::cos(currentAngle_), radius_ * ::sin(currentAngle_));
}
};
int main()
{
GenerateCircleCoOrds circle(-200, -200);
RECT rect;
if(::GetWindowRect(::GetDesktopWindow(), &rect)) {
for(int x = 0; x < 200; ++x) {
Point point = circle.Step(6.28/100);
::SetCursorPos(rect.right/2 + point.X, rect.bottom/2 - point.Y);
::Sleep(15);
}
}
return 0;
} |
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Deltron Z
Expert Cheater
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Joined: 14 Jun 2009
Posts: 164
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| Posted: Mon Mar 08, 2010 5:00 am Post subject: |
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| Tvirusx1 wrote: | Ooops lol!
Ok I've got that with the Trigonometry.
But what do you mean with:
| Quote: | | With 0 degrees being in the same place as in your draw, simply decrease 90 from degrees before you calculate the location. just use your head. |
|
Say that you're making an analog clock, and you want 0 degrees to point to 3 O'clock (as in your draw), simply increase the degrees by 90, then it'll point to 3 O'clock (90 degrees) when the input (or any value used to calculate the right time's degrees) should point to 12:00 O'clock. it's useful when, for example, you have a character in a 3D world and you want side view of it, or add 180 degrees for viewing it from the back.
| Tvirusx1 wrote: | I want my Cursor to start moving from the line (CPX,CPY,X,Y)
(In the image it was x1,y1,x2,y2)
CPX is the Current X pos.
CPY is the Current Y pos.
X is the x pos of the center point of the Circle.
Y is the y pos of the center point of the Circle.
My code so far:
| Code: | #include <iostream>
#include <windows.h>
#include <math.h>
using namespace std;
...
...
X = round(rad * cos([b]deg[/b]));
Y = round(rad * sin([b]deg[/b]));
...
... |
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sin and cos functions from Math.h takes Radians, you passed the parameter as degrees. simply convert by dividing by 180 (half a rotation in degrees) and multipy by PI. (half a rotation in radians, 3.14...)
I'd do it like this: (spiral  )
| Code: | int Width = GetSystemMetrics(SM_CXSCREEN);
int Height = GetSystemMetrics(SM_CYSCREEN);
int X, Y, Degrees = 0;
double Radius = 1;
while (Radius < min(Width, Height))
{
X = (int)(Radius * sin((double)(Degrees % 360) / 180.0 * 3.14));
Y = (int)(Radius * cos((double)(Degrees % 360) / 180.0 * 3.14));
SetCursorPos(X + Width / 2, Y + Height / 2);
Degrees++;
Radius += 0.5;
Sleep(5);
} |
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A_jj74
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Joined: 14 Nov 2009
Posts: 41
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| Posted: Mon Mar 08, 2010 6:56 am Post subject: |
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| Quote: | | Say that you're making an analog clock, and you want 0 degrees to point to 3 O'clock (as in your draw), simply increase the degrees by 90, then it'll point to 3 O'clock (90 degrees) when the input (or any value used to calculate the right time's degrees) should point to 12:00 O'clock. it's useful when, for example, you have a character in a 3D world and you want side view of it, or add 180 degrees for viewing it from the back. |
It wasn't me who decided that 0 should be at 3 O'Clock lol.
C++ calculates 0 Degrees/Radians at 3 O'Clock.
What I was trying to do was to set the "0" to the direction of My X and Y pos (CPX,CPY).
I think this code should do, it's not too accurate though.
| Code: | #include <iostream>
#include <windows.h>
#include <math.h>
using namespace std;
float PI = 3.14159265358979323846264338327950288;
float DegreesToRadians(float Degrees)
{
float Radians;
Radians = Degrees * (PI/180);
return Radians;
}
float RadiansToDegrees(float Radians)
{
float Degrees;
Degrees = Radians * (180/PI);
return Degrees;
}
void Circle(int CPX, int CPY, int X, int Y, int Radius)
{
float Degrees = 0;
if((CPX<X)&&(CPY==Y))
Degrees = 180;
if((CPX<X)&&(CPY<Y))
Degrees = 225;
if((CPX<X)&&(CPY>Y))
Degrees = 135;
if((CPX==X)&&(CPY>Y))
Degrees = 90;
if((CPX>X)&&(CPY>Y))
Degrees = 45;
if((CPX>X)&&(CPY==Y))
Degrees = 0;
if((CPX==X)&&(CPY>Y))
Degrees = 270;
if((CPX>X)&&(CPY<Y))
Degrees = 315;
float Radians = DegreesToRadians(Degrees);
int dx = X;
int dy = Y;
float MaxDegrees = 360+Degrees; //+ deg to make it a full circle, if the cursor starts at a higher degree than 0
Sleep(5);
do
{
X = round(Radius * cos(Radians));
Y = round(Radius * sin(Radians));
SetCursorPos(X+dx, Y+dy);
Radians += 0.01;
Degrees = RadiansToDegrees(Radians);
Sleep(2);
}
while (Degrees <= MaxDegrees);
}
int main()
{
cout << "Upper left" << endl;
Circle(100,100,200,200,100);//upper left
cout << "Bottom right" << endl;
Circle(300,300,200,200,100);//bottom right
cout << "Bottom left" << endl;
Circle(100,300,200,200,100);//Bottom left
cout << "Upper right" << endl;
Circle(300,100,200,200,100);
cin.get();
return 0;
} |
If theres a way I could improve it please let me know  .
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Deltron Z
Expert Cheater
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Posts: 164
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| Posted: Mon Mar 08, 2010 7:27 am Post subject: |
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I don't understand what you were trying to do in this piece of code...
Try using the code I've posted before and see what happens. 
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A_jj74
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Joined: 14 Nov 2009
Posts: 41
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| Posted: Mon Mar 08, 2010 11:52 am Post subject: |
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| Deltron Z wrote: | I don't understand what you were trying to do in this piece of code...
Try using the code I've posted before and see what happens. |
I have tried it, it moves in a Spiral, but thats not what I need =/.
(Although it will be useful for me in the future)
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Deltron Z
Expert Cheater
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| Posted: Mon Mar 08, 2010 12:07 pm Post subject: |
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So simply use a constant radius. use your head. 
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A_jj74
Cheater
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| Posted: Mon Mar 08, 2010 8:07 pm Post subject: |
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| Deltron Z wrote: | | So simply use a constant radius. use your head. |
I have posted a working code at Post #9.
But it needs to be improved =/.
@Your Spiral code, I know I would have to use a Constant Radius.
I somewhat got it.
Close Thread?
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