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kosstr12
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 Posted: Thu Jan 15, 2009 5:26 pm Post subject: Help with this formula |
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Okay, I can't remember what the formula is, so I need some help. Let's say n is any specified number. If n multiplies itself times 1.25 everytime it goes up, what is the formula to calculate this?
Thanks,
Koss
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Neo.
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| Posted: Thu Jan 15, 2009 5:26 pm Post subject: |
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the forumla is "1337"
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kosstr12
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| Posted: Thu Jan 15, 2009 5:28 pm Post subject: |
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| Mint25642 wrote: | | the forumla is "1337" |
...No...No it's not.
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Neo.
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| Posted: Thu Jan 15, 2009 5:29 pm Post subject: |
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the forumla for everything in the universe is "1337"
it sed so on a tramps cardboard box i was walking past the otha day.
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compactwater
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| Posted: Thu Jan 15, 2009 5:34 pm Post subject: |
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n1.25
n*1.25
Something along those lines, not really sure what you're asking for.
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[GN]Xitra
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| Posted: Thu Jan 15, 2009 5:34 pm Post subject: |
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| OMFG HAI GUIZ! WUZZUP RAINBOW LOL
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kosstr12
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| Posted: Thu Jan 15, 2009 5:41 pm Post subject: |
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| compactwater wrote: | n1.25
n*1.25
Something along those lines, not really sure what you're asking for. |
Maybe?
Here is an example if n is being multiplied times 1.25 each time:
(n) = ?
(1) = 1.25
(2) = 1.5625
(3) = 1.953125
(4) = 2.44140625
Get what I'm saying now?
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Blank
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| Posted: Thu Jan 15, 2009 5:44 pm Post subject: |
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| Mint25642 wrote: | the forumla for everything in the universe is "1337"
it sed so on a tramps cardboard box i was walking past the otha day. |
Everyone knows its "42", retard.
Wait, no...
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Neo.
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| Posted: Thu Jan 15, 2009 5:45 pm Post subject: |
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| Mint25642 wrote: | | the forumla is "1337" |
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Blank
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| Posted: Thu Jan 15, 2009 5:47 pm Post subject: |
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| kosstr12 wrote: | | compactwater wrote: | n1.25
n*1.25
Something along those lines, not really sure what you're asking for. |
Maybe?
Here is an example if n is being multiplied times 1.25 each time:
(n) = ?
(1) = 1.25
(2) = 1.5625
(3) = 1.953125
(4) = 2.44140625
Get what I'm saying now? |
Did you pull these numbers out of your ass or is that what n is supposed to be equal to when tied with 1.25?
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kosstr12
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| Posted: Thu Jan 15, 2009 5:50 pm Post subject: |
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| Blank wrote: | | kosstr12 wrote: | | compactwater wrote: | n1.25
n*1.25
Something along those lines, not really sure what you're asking for. |
Maybe?
Here is an example if n is being multiplied times 1.25 each time:
(n) = ?
(1) = 1.25
(2) = 1.5625
(3) = 1.953125
(4) = 2.44140625
Get what I'm saying now? |
Did you pull these numbers out of your ass or is that what n is supposed to be equal to when tied with 1.25? |
That is not me pulling numbers out of my ass. That is me multiplying 1.25 times 1.25, then that times 1.25, then that times 1.25, etc. etc. I want to know the formula to do this.
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lucid
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| Posted: Thu Jan 15, 2009 5:54 pm Post subject: |
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| If all you are doing is multiplying it by 1.25 then wouldn't the n=1? Because 1*1.25=1.25 then so on and so on right?
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:^)
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| Posted: Thu Jan 15, 2009 5:56 pm Post subject: Re: Help with this formula |
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| kosstr12 wrote: | Okay, I can't remember what the formula is, so I need some help. Let's say n is any specified number. If n multiplies itself times 1.25 everytime it goes up, what is the formula to calculate this?
Thanks,
Koss |
nē(1.25)=
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kosstr12
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| Posted: Thu Jan 15, 2009 5:56 pm Post subject: |
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| Shigure wrote: | | If all you are doing is multiplying it by 1.25 then wouldn't the n=1? Because 1*1.25=1.25 then so on and so on right? |
No, because it's multiply 1.25 times the previous number. I'm starting to remember a little bit of it... Something like this I think:
(n) = n-1*1.25
Does that sound right?
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