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Error when searching with XOR Lua formula in the search box.

 
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skynet888
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PostPosted: Wed Jun 01, 2022 6:59 pm    Post subject: Error when searching with XOR Lua formula in the search box. Reply with quote
Error when searching with XOR Lua formula in the search box. Or, CE does not tell the user how to use the XOR lua formula

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ParkourPenguin
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PostPosted: Wed Jun 01, 2022 9:01 pm    Post subject: Reply with quote
I don't know where you got "XOR" from. The Lua xor operator is ~

Search for 0xB0 ~ 0x22
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skynet888
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PostPosted: Thu Jun 02, 2022 8:42 pm    Post subject: Reply with quote
ParkourPenguin wrote:
I don't know where you got "XOR" from. The Lua xor operator is ~

Search for 0xB0 ~ 0x22

The problem is: we do not care who is on the left side of "xor". We just want to keep all the results that satisfy "xor B0==22".
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ParkourPenguin
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PostPosted: Thu Jun 02, 2022 10:33 pm    Post subject: Reply with quote
That isn't a problem. What you wrote is the same thing as what I wrote.
Code:
let `~` = XOR
Search for all x such that `x ~ 0xB0 == 0x22`

x ~ 0xB0 == 0x22
x ~ 0xB0 ~ 0xB0 == 0x22 ~ 0xB0
x ~ (0xB0 ~ 0xB0) == 0x22 ~ 0xB0
x ~ 0 = 0x22 ~ 0xB0
x = 0x22 ~ 0xB0
Search for all x such that `x = 0x22 ~ 0xB0`
All of the above operations come from the fact that the integers equipped with xor is an abelian group. also `0x22 ~ 0xB0 == 0xB0 ~ 0x22`

If you want something more complicated (e.g. if the xor key changes), use a custom type.
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Dark Byte
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PostPosted: Fri Jun 03, 2022 2:47 am    Post subject: Reply with quote
(value ~ 0xb0) == 0x22
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