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sir-gunny
Advanced Cheater
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Joined: 15 Mar 2012
Posts: 81
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 Posted: Fri Mar 18, 2022 11:27 am Post subject: Recreating a string with references from a string (as table) |
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Hello.
I would like to use the references from a string to create a new string from it. The references are in a table. The strings have sometimes several references and sometimes none at all. Sometimes there are references that are not in the table. I do not know what to do at the moment. I hope you can help me. Sorry for my english, I use deepl.
Example:
| Code: | MyString = [[{1101,2344} - {1102,874} \({3501,78} a {457,57}{74,978}\)!]]
MyBigTable = { [49] = {
[1101] = {[2344] = [[Hello]]},
[457] = {[57] = nil}, -- {457,57} does not exist in the table
[1102] = {[874] = [[World]]},
[3501] = {[78] = [[{8745,589} {84,987}]]},
[8745] = {[589] = [[This]]},
[84] = {[987] = [[is]]},
[74] = {[978] = [[test!]]}
}} |
| Code: | | Hello - World (This is a test!)! |
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sir-gunny
Advanced Cheater
![]() Reputation: 0
Joined: 15 Mar 2012
Posts: 81
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| Posted: Sat Mar 19, 2022 3:10 pm Post subject: |
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Hi.
I have tested around a bit and found this solution for me. Probably not the nicest but OK for me. 
| Code: | function stringReplaceFromTable(sString,tTable)
local d1,d2 = sString:match("{(%d+),(%d+)}")
local sTemp = sString:gsub("{%d+,%d+}",tTable[tonumber(d1)] and tTable[tonumber(d1)][tonumber(d2)] or "",1)
if sTemp:match("{%d+,%d+}") then
return stringReplaceFromTable(sTemp,tTable)
else
sTemp = sTemp:gsub("\\","")
return sTemp
end
end
print(stringReplaceFromTable(MyString,MyBigTable[49])) |
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