Cheat Engine

[C9Angelo]

hello, alle! i need some assistance creating a script>

Let's say that Badge A and Badge B share a common address. There are 5 states that a badge can be in: Off, Bronze, Silver, Gold, and Diamond. Badge A follows the following: Off:0, Bronze:8, Silver:16, Gold:24, Diamond:32. Badge B follows the following: Off:0, Bronze: 1, Silver:2, Gold:3, Diamond:4. The issue that I am running into is that if I try to change Badge B to Bronze, it will change the value to 1, meaning that I cannot also have Badge A as Bronze. The solution to this would be to have the options add and subtract from the initial value (0) as opposed to changing it to a direct number.

if anyone knows how to do this, please share it with me! thank you!

i also would like to note that these are in the form of a drop down. so i would go to the drop down list in Badge A, click on Diamond (which would make it 32), and then i could go to the drop down list on Badge B, click on Diamond and it would make it 36 as opposed to 4.

[panraven]

It should be make of bitfields,
A is from bit 0-bit2, (In CE make memory record of Binary type, set bit start 0, length 3),
B is bit 3-bit 7 (make nother memory record of same address, bit start 3 length 5).

They together make use of all 8 bit of the byte in the same address.

A part is simpler, we use directly the value.

0:off
1:Bronze
2:Silver
3:Gold
4:Diamond

B part need a bit modification, for from bitfields B's view,
the value 8 (bit 3 set in whole byte view) is bit 0,
when it set, it is 1 in view inside the B part bitfield,
so 8->1, 16->2, 32->4,64->8 in setting up the dropdown list
ie.
0:off
1:Bronze
2:Silver
4:Gold
8:Diamond

OOPS:
I overlook that 8,16,24,32 as 8,16,32,64
It should be similar, modified as
0:off
1:Bronze
2:Silver
3:Gold
4:Diamond

And bitfields B should set as bit start 3, length 3 (fixed).

[C9Angelo]

[panraven]

Have you try to make the 2 BINARY type memory record?

The purpose is to make the two memory record value INDEPENDENCE to each other, so that value change in one value doesn't affect other.
It is the same as any other independence memory record values,
where you specify ADDRESS in BYTE UNITs;
except that CE provide the Binary type we can specify ADDRESS (or where the value is) in BIT UNITs.

(I somehow mistaken A & B, please swap them ~_~)

[C9Angelo]

[panraven]

Are you sure they represent the same data?
For instance, it may be there are actually A/B/C/D badge,
where A/B is for common unit with A/B occupy <0-2bit><3-5bit>a byte at offset 0,
and while C/D is for elite unit occupy <2-4bit><5-7bit> at offset 1,
but A/B badge doesn't occur with C/D badge,
so the difference?

To get the bit start and length,
you can check the smallest and larges non-zero BIT value (power of 2) within the bitfield.
For instance 0,16,32,48,64 -> smallest 16 -> bit 4 (bit 0 is 1st bit, bit 4 is 5th),
largest 64->bit 6, length = (6 - 4) + 1 = 3.
In case of largest value is something like 127 (not power of 2), then its largest non-zero BIT value is still 64.

OOPS:
I found the value 16 (bit 4) appeared both in your
"badge A will be 0, 16, 32, 48, 64 and badge B will be 0, 4, 8, 12, 16"
They are not independent, are they the right value?
(ie. I'm wrong again in above C/D badge example, it should be bit4-6/bit2-4 , overlapped bit4)

[C9Angelo]