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How to get String from DWORD (Pointer+Offset) [C++]

 
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MultiTasking
How do I cheat?
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PostPosted: Wed Jan 09, 2019 1:30 pm    Post subject: How to get String from DWORD (Pointer+Offset) [C++] Reply with quote

Good day,
I'm trying to get a String from a Pointer as pointed out in this video:
https: //ww w.youtube. com/watch?v=oC2-yjTli7g

But I have problems in getting the pointer and offset correctly:

http s://i.imgur. com/hqCB2Hx.png

Code:
   DWORD Pointer2 = 0x1D8530;
   DWORD Offset3 = 0x3C;
   char* Text = (char*)(*(DWORD*)Pointer2 + Offset3); //1 Offset
   large_img = std::string(Text);


Can anyone help me with this?

Regards



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OldCheatEngineUser
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PostPosted: Wed Jan 09, 2019 3:45 pm    Post subject: Reply with quote

MultiTasking wrote:
...
https://i.imgur.com/hqCB2Hx.png
https://www.youtube.com/watch?v=oC2-yjTli7g


010D8530 is not the static address, the static address is "nro.exe"+002588D8.

where nro.exe is equal to image base address, and 002588D8 is the offset from image base to some address that holds 010D8530.

also you have a typo there:
Code:
DWORD Pointer2 = 0x1D8530 // it should be 010D8530


assuming image base address is equal to 00400000, then add 002588D8 to it and it should be 006588D8.

so 006588D8 holds the address 010D8530, and 010D8530+3C equal to 010D856C.

010D856C holds the string [email protected], so you have to adjust things in order to read string properly.

also keep in-mind, if the image base is not fixed (i.e. relocatable image base) then you have to find another way to get your static address.

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MultiTasking
How do I cheat?
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Joined: 09 Jan 2019
Posts: 3

PostPosted: Wed Jan 09, 2019 4:37 pm    Post subject: Reply with quote

Quote:
also you have a typo there:


If I put:

Code:
010D8530
instead of
Code:
0x1D8530
the compiler (MSVS2017) throw me the follow error:
Code:
invalid literal suffix 'D8530'; literal operator or literal operator template 'operator ""D8530' not found


I'm not really skillful programming but I based me in other Address that I get:

Code:
AString = "Value " + std::to_string(*reinterpret_cast<int*>(0x010D93D8));


Address: 010D93D8=4012

And indeed "AString" is equal to "Value: 4012"

Can you explain me this?
Why 0x010D93D8 is equal to 010D93D8?

And thank you for your reply!
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OldCheatEngineUser
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PostPosted: Wed Jan 09, 2019 5:01 pm    Post subject: Reply with quote

MultiTasking wrote:
If I put:

Code:
010D8530
instead of
Code:
0x1D8530
the compiler (MSVS2017) throw me the follow error:
Code:
invalid literal suffix 'D8530'; literal operator or literal operator template 'operator ""D8530' not found

i did not say to remove the 0x? prefix, 1D8 is not the same as 10D8.

and im not sure what you are doing here, or where you got 010D93D8 from.

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MultiTasking
How do I cheat?
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PostPosted: Wed Jan 09, 2019 6:00 pm    Post subject: Reply with quote

Quote:
i did not say to remove the 0x? prefix, 1D8 is not the same as 10D8.

Oh my bad!

Quote:
and im not sure what you are doing here, or where you got 010D93D8 from.


With 010D93D8 I wanted read the int value and pass it to string (as you can see here):

Code:
std::string AString = "Value " + std::to_string(*reinterpret_cast<int*>(0x010D93D8));

It worked!

And now I want to do the same with 010D856C but in this case isn't a int value, is a text (or string)

I tried doing the following:

Code:
std::string AString = "String Name " + std::to_string(*reinterpret_cast<char*>(0x010D856C));

Expecting a result equal to "String Name [email protected]"
But the result is "String Name 109"
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