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Demonarke
Cheater
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Joined: 12 Aug 2013
Posts: 31
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 Posted: Fri Jul 15, 2016 12:54 pm Post subject: Regular expressions |
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Hey, I'm trying to do a scan search to replace "if" variables, the variable could be this :
if Strength>=40
goto
something
but the thing is that I can't just change all the variables it would take a tremendously amount of time, so what I wanted to do that you can do in notepad, is use [0-9] so I would want to search this on cheat engine >=[1-9] and it would scan every "skill check" basically. But cheat engine doesn't seem to be able to do it, or can it ?
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cooleko
Grandmaster Cheater
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Joined: 04 May 2016
Posts: 717
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| Posted: Fri Jul 15, 2016 2:05 pm Post subject: |
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Your request is vague, are you trying to search lua? Code that you have created or are you trying to search the game code?
If you are searching lua, then just paste your script into word or notepad and use replace all.
If you are searching game code, then you should not do what you are trying to do.
Strength, will likely have an address, but the game code CE sees isnt "If STR >= 40" it will likely be
| Code: | mov eax, [Str Address]
cmp eax, [Str value]
jge StrCheckSucceeded
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The above is simple, there are many ways, some much more complicated, for a game to implement an attribute check.
I recommend you brush up on the use of AOBs, in order to perform what you want.
http://forum.cheatengine.org/viewtopic.php?t=570083
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Demonarke
Cheater
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Joined: 12 Aug 2013
Posts: 31
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| Posted: Fri Jul 15, 2016 2:19 pm Post subject: |
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| Sure probably the code is going to be like that, but couldn't I just change it's string with cheat engine ? Cause the code is definitely "if STR>=40" but, there are many checks in the game, some would be relationship checks, skill checks, and the thing is that they are all functioning on this ">=" so what i thought I could do would be to just search this on string ">=" and a number between [1-9] so it would show me >= 40, >=30, >=60 basically every possible combination of this string. I don't know if you get where I'm going but for those who know this regular expression it's really simple, it's like using [a-Z] searching for every possible letter possible.
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Zanzer
I post too much
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Joined: 09 Jun 2013
Posts: 3278
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| Posted: Fri Jul 15, 2016 2:48 pm Post subject: |
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Ctrl+Alt+L
| Code: | local aob = AOBScan("3E 3D")
for i=1,aob.Count-1 do
print(readString(aob[i], 32))
end
aob.Destroy() |
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cooleko
Grandmaster Cheater
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Joined: 04 May 2016
Posts: 717
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| Posted: Fri Jul 15, 2016 4:49 pm Post subject: |
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| Demonarke wrote: | | Sure probably the code is going to be like that, but couldn't I just change it's string with cheat engine ? Cause the code is definitely "if STR>=40" but, there are many checks in the game, some would be relationship checks, skill checks, and the thing is that they are all functioning on this ">=" so what i thought I could do would be to just search this on string ">=" and a number between [1-9] so it would show me >= 40, >=30, >=60 basically every possible combination of this string. I don't know if you get where I'm going but for those who know this regular expression it's really simple, it's like using [a-Z] searching for every possible letter possible. |
Why isnt the code "if str > 39" or "if not str < 40" there are going to be thousands of compares. Most of them are not going to be about ability checks.
I think you are tackling the problem from the wrong angle. However, you never told us the problem outside of you want to search high level code that isnt visible to cheat engine.
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Demonarke
Cheater
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Joined: 12 Aug 2013
Posts: 31
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| Posted: Fri Jul 15, 2016 7:04 pm Post subject: |
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| Zanzer seems to be the person who is the closest of achieving what I want, problem is, I don't understand the code :-/ could you perhaps explain to me what the code does ? It's functions ?
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ParkourPenguin
I post too much
 Reputation: 152
Joined: 06 Jul 2014
Posts: 4702
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| Posted: Fri Jul 15, 2016 8:08 pm Post subject: |
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| Code: | local aob = AOBScan("3E 3D") -- scans for the string ">="
for i=1,aob.Count-1 do -- loop through the results
print(readString(aob[i], 32)) -- print the string representation of the results (max 32 chars)
end -- end loop
aob.Destroy() -- free the results |
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I don't know where I'm going, but I'll figure it out when I get there. |
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Demonarke
Cheater
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Joined: 12 Aug 2013
Posts: 31
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| Posted: Sat Jul 16, 2016 8:23 am Post subject: |
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| When I scan >=40 I find something, and when I go to memory view, i can see the string if STR>=40, I will edit it and I will get what I want, basically put if STR>=0 but there are too many variables for me to find them all, this is not always going to be 40, and it isn't always strength. What I wanted to know is if I could scan between a range of number [1-9] while having >= behind so I would scan >= "every number possible" and the list would show me >= and every number possible, and I would just edit them out so no checks in the game. When I do your aob scan I don't find any string that looks like the string I see in memory view.
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panraven
Grandmaster Cheater
![]() Reputation: 62
Joined: 01 Oct 2008
Posts: 958
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| Posted: Sat Jul 16, 2016 10:32 am Post subject: |
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May try like:
| Code: |
local test = true -- no write to memory, but for debug print if true
local aob = AOBScan(("if "):byte(1,-1))
if aob~=nil then
for i=0,aob.Count-1 do
-- read text from memory
local code = readString(aob[i],32)
-- capture desired pattern
local posBegin, LHS, cmpOps, RHS, posEnd, others = code:match('^if%s()(%s*.-%s*)([><=]+)(%s*%d+%s*)()%s(%S.*)')
-- do text modification if pattern matched
if LHS~=nil then
-- further extract pattern content, ie. this is for format: if [VarName] [compare ops] [number]
local varname,number,newexp = LHS:match('^%s*(.-)%s*$'),tonumber(RHS:match('(%d+)') or '')
if number then
if varname=='STRENGTH' then
newexp = 'true'
elseif varname=='DAMAGE' then
newexp = LHS..cmpOps..(number-10)
end
-- if no match, left newexp no value
end-- if number
if newexp then
-- space adjust, so that the modified text can be write back safely.
local spcAdjust = posEnd-posBegin - newexp:len()
print(spcAdjust)
if spcAdjust>= 0 then
newexp = string.rep(' ',spcAdjust)..newexp
if test==true then -- debug print
print('aob #'..i)
print('\t','if '..newexp..' '..others)
print('\t',code)
else -- write back memory
writeString(tonumber(aob[i],16)+posBegin-1,newexp)
end
end
end-- if newexp
end-- if LHS
end -- for aob
aob.Destroy()
end-- if aob
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NOTE:
Lua 5.3 re pattern
https://www.lua.org/manual/5.3/manual.html#6.4.1
pattern () is for string position, check last paragraph of #6.4.1
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