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Ludwig
Advanced Cheater
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Joined: 10 Jan 2016
Posts: 68
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 Posted: Sun Feb 28, 2016 9:15 am Post subject: finding a value of a different type in a trainer |
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hi...
in my trainer...to do a check on an aob i use something like
if AOBScan("2c ?? 0e 25 8c 02") then
do whatever
end
but
in CE..in 4byte mode i can scan for a value like 17736243
...how can i do it in trainer to scan for a value of another type...not an aob?
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panraven
Grandmaster Cheater
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Joined: 01 Oct 2008
Posts: 958
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| Posted: Sun Feb 28, 2016 9:42 am Post subject: |
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May try convert the number to aob pattern, ie.
17736243 -> 0x10ea233 -> 33 a2 0e 01, but the scan is slow, and if alignment matter may include false result.
Alternatively, @main.lua, there is memscan class,
| Code: | MemScan Class (Inheritance: Object)
getCurrentMemscan() : Returns the current memory scan object. If tabs are used the current tab's memscan object
createMemScan(progressbar OPTIONAL) : Returns a new MemScan class object
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Ludwig
Advanced Cheater
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Joined: 10 Jan 2016
Posts: 68
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| Posted: Sun Feb 28, 2016 9:55 am Post subject: |
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| panraven wrote: | May try convert the number to aob pattern, ie.
17736243 -> 0x10ea233 -> 33 a2 0e 01, but the scan is slow, and if alignment matter may include false result.
Alternatively, @main.lua, there is memscan class,
| Code: | MemScan Class (Inheritance: Object)
getCurrentMemscan() : Returns the current memory scan object. If tabs are used the current tab's memscan object
createMemScan(progressbar OPTIONAL) : Returns a new MemScan class object
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thnx...it worked
btw...how do we give rep here...i can only view rep given...
then
| Code: | function DEC_HEX(IN)
local B,K,OUT,I,D=16,"0123456789ABCDEF","",0
while IN>0 do
I=I+1
IN,D=math.floor(IN/B),math.mod(IN,B)+1
OUT=string.sub(K,D,D)..OUT
end
return OUT
end
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will convert desimal to integer...which i then put into a string...reverse it...check length if even...if not, add a "0"...then break it up into 2 chars with spaces inbetween...which will for my aob...
am i correct, or is ther an easier command line to do it?
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panraven
Grandmaster Cheater
![]() Reputation: 62
Joined: 01 Oct 2008
Posts: 958
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| Posted: Sun Feb 28, 2016 11:04 am Post subject: |
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Simpler way to convert a number to a hex string is
| Code: | | string.format("%X",number) |
May try this
| Code: | function num2aob(n,nbyte)
assert(type(n)=='number',"num2aob,input not a number:"..tostring(n))
nbyte = type(nbyte)=='number' and nbyte or 4
local ndigit,aob = nbyte*2,{}
local hex = string.format("%0"..ndigit.."X",n) -- at least ndigit
for i=ndigit,1,-2 do -- reverse order
aob[1+#aob] = hex:sub(i-1,i)
end
return table.concat(aob,' ')-- join the parts
end
-- test
-- default dword -> 4 bytes
print(num2aob(17736243))
-- specify qword -> 8 bytes
print(num2aob(17736243,8))
print(num2aob(-17736243,8)) |
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Ludwig
Advanced Cheater
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Joined: 10 Jan 2016
Posts: 68
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| Posted: Sun Feb 28, 2016 12:33 pm Post subject: |
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| panraven wrote: | Simpler way to convert a number to a hex string is
| Code: | | string.format("%X",number) |
May try this
| Code: | function num2aob(n,nbyte)
assert(type(n)=='number',"num2aob,input not a number:"..tostring(n))
nbyte = type(nbyte)=='number' and nbyte or 4
local ndigit,aob = nbyte*2,{}
local hex = string.format("%0"..ndigit.."X",n) -- at least ndigit
for i=ndigit,1,-2 do -- reverse order
aob[1+#aob] = hex:sub(i-1,i)
end
return table.concat(aob,' ')-- join the parts
end
-- test
-- default dword -> 4 bytes
print(num2aob(17736243))
-- specify qword -> 8 bytes
print(num2aob(17736243,8))
print(num2aob(-17736243,8)) |
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hmm...nice...a few more things to research...
thnx a lot for your hlp...
writing it to a txt file...i tried
| Code: | local file = io.open("c:\aob.txt", "w")
file:write(newstr)
file:close() |
where "newstr" is the aob we created
but it gives me an error...
"Error:[string "function trainerinput()..."]:141: attempt to index local 'file' (a nil value)"
for line "file:write(newstr)"
viewtopic.php?t=588044
answered the problem at hand...thnx...
| Code: | file = io.open("c:\\aob.txt", "w")
file:write(newstr)
file:close() |
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