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Problems finding values at Labyronia RPG

 
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DrackoShen
How do I cheat?
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Joined: 18 Aug 2015
Posts: 3

PostPosted: Tue Aug 18, 2015 8:44 am    Post subject: Problems finding values at Labyronia RPG Reply with quote

Hi guys!

I'm trying to hack Labyronia RPG, but I can't find the values (health and money) to modify.

I searched all types of value (exact, increased, decreased, doble, float, byte...), but the value does not appear.

I think that the game don't have another process.

Any ideas?
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STN
I post too much
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Joined: 09 Nov 2005
Posts: 2576

PostPosted: Tue Aug 18, 2015 11:13 am    Post subject: Reply with quote

Did you do an unknown value search ?
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DrackoShen
How do I cheat?
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Joined: 18 Aug 2015
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PostPosted: Tue Aug 18, 2015 11:28 am    Post subject: Reply with quote

STN wrote:
Did you do an unknown value search ?


Yes, but the combats, aren't long enough for this method... and with money... I'm too poor Laughing

Too many variables...
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Chiados
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Joined: 05 Feb 2015
Posts: 47

PostPosted: Wed Aug 19, 2015 3:47 am    Post subject: Reply with quote

Say you have 300g. You would then multiply 300x2. That leaves you with 600. Now search 601. For most things you will need to do that. Includes HP and AP as well.

Edit: Just search 4byte values. It's the quickest.
Edit 2: Don't set your gold too high, it tends to crash the game. Just make it around 200k. You will never spend more than that through out the game.
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DrackoShen
How do I cheat?
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Joined: 18 Aug 2015
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PostPosted: Wed Aug 19, 2015 9:32 am    Post subject: Reply with quote

Chiados wrote:
Say you have 300g. You would then multiply 300x2. That leaves you with 600. Now search 601. For most things you will need to do that. Includes HP and AP as well.

Edit: Just search 4byte values. It's the quickest.
Edit 2: Don't set your gold too high, it tends to crash the game. Just make it around 200k. You will never spend more than that through out the game.


Shocked Shocked Shocked

That works!!

I didn't know those games use that method for values

Thank!! Very Happy Very Happy
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Cake-san
Grandmaster Cheater
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Joined: 18 Dec 2014
Posts: 541
Location: Semenanjung

PostPosted: Thu Aug 27, 2015 9:37 am    Post subject: Reply with quote

Dark Byte wrote:
If that's true then if you're lazy you can just use the binary type to find it

Just wondering, is it always +1 ? Are there cases where it's just *2? Because what you describe is just a bitshift by 1 and there's a random bit in front of it

Here's a custom type (adapted from my *8 custom type) that may work with this thing
Code:

alloc(TypeName,256)
alloc(ByteSize,4)
alloc(PreferedAlignment, 4)
alloc(ConvertRoutine,1024)
alloc(ConvertBackRoutine,1024)

TypeName:
db 'RPG VX type',0

ByteSize:
dd 4

PreferedAlignment:
dd 1


//The convert routine should hold a routine that converts the data to an nteger (in eax)
//function declared as: stdcall int ConvertRoutine(unsigned char *input);

//Note: Keep in mind that this routine can be called by multiple threads at the same time.

ConvertRoutine:
[32-bit]
push ebp
mov ebp,esp
push ecx
mov ecx,[ebp+8]
[/32-bit]

//at this point ecx contains the address where the bytes are stored

//put the bytes into the eax register
mov eax,[ecx] //second fun fact, addressing with 32-bit registers doesn't work in 64-bit, it becomes a 64-bit automatically (most of the time)
shr eax,1 //shift right by 1 bit (divide by 2)

//and now exit the routine
[64-bit]
ret
[/64-bit]
[32-bit]
pop ecx
pop ebp
ret 4
[/32-bit]

//The convert back routine should hold a routine that converts the given integer back to a row of bytes (e.g when the user wats to write a new value)
//function declared as: stdcall void ConvertBackRoutine(int i, unsigned char *output);
ConvertBackRoutine:
[32-bit]
push ebp
mov ebp,esp
push edx //save the registers
push ecx
mov edx,[ebp+0c]
mov ecx,[ebp+08]
[/32-bit]

//at this point edx contains the address to write the value to
//and ecx contains the value

push eax
push edx


mov edx,[edx] //edx now contains the original value
and edx,1 //only save the first bit

mov eax,ecx //eax gets the user input value
shl eax,1 //shift left by 1 bit (multiply by 2)
or eax,edx //add the bits of the original value

pop edx
mov [edx],eax //write the new value into the old value
pop eax

[64-bit]
//everything is back to what it was, so exit
ret
[/64-bit]

[32-bit]
//cleanup first
pop ecx
pop edx
pop ebp
ret 8
[/32-bit]


right-click the right of value type in cheat engine,define new custom type(AA),copy-paste this script replacing the (AA),OK. -_-
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