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Woza
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Joined: 08 Sep 2012
Posts: 12
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 Posted: Thu Aug 29, 2013 12:52 pm Post subject: Multiple Lua breakpoints? |
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| Code: | addys = {}
addys.enemies = "89 48 04 8B 8D 24 FF FF FF 89 48 08 E9 73 00 00 00"
addys.player = "66 0F D6 AB 00 01 00 00 F3 0F 7E 6E 18 66 0F D6 AB 08 01 00 00"
enemies = {}
player = {}
function debugger_onBreakpoint()
if (EIP == addys.enemies) then
enemies[EAX] = {x = readFloat(EAX), y = readFloat(EAX+0x04), z = readFloat(EAX+0x08)}
return 1
end
if (EIP == addys.player) then
if (enemies[0] ~= nil) then
writeFloat(EBX+player.x, enemies[0].x)
writeFloat(EBX+player.y, enemies[0].y+1)
writeFloat(EBX+player.z, enemies[0].z)
end
return 1
end
debug_continueFromBreakpoint(co_run) -- continue execution
return 0 -- let CE know we handled breakpoint, no need to update debugger form
end
for k,v in pairs(addys) do
addys[k] = AOBScan(v)
if addys[k] == nil then print("Error: couldnt find AOB " .. v) else addys[k] = tonumber(addys[k][0],16)
end
end
player.x = 0xFC -- player offsets
player.y = 0x104
player.z = 0x108
debugProcess()
debug_setBreakpoint(addys.enemies)
debug_setBreakpoint(addys.player) |
Here is my code. I have 2 opcodes; one writes to the players coordinates and the other one to the enemies coordinates. I am trying to make a telekill script but cant seem to get 2 breakpoints at once. The enemies addresses sometimes switch when they die, thats why I need to update them with a breakpoint.
Can someone help?
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Dark Byte
Site Admin
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Joined: 09 May 2003
Posts: 25788
Location: The netherlands
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| Posted: Thu Aug 29, 2013 1:14 pm Post subject: |
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Have you confirmed that addys.enemies and addys.player actually contain valid addresses ?
setBreakpoint can either take a decimal integer/number or a ceformatted string (hexadecimal string or registered symbol name)
e.g
try: addys[k] = addys[k][0]
that way addys[k] gets the ceformatted string
(Also, the Stringlist Object returned by AOBScan should be freed if you don't want a memory leak. So I recommend using local variables instead of overwriting existing ones so you can actually free it when done with the list)
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Woza
Newbie cheater
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Joined: 08 Sep 2012
Posts: 12
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| Posted: Thu Aug 29, 2013 2:37 pm Post subject: |
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| Code: | addys = {}
addys.enemies = "89 48 04 8B 8D 24 FF FF FF 89 48 08 E9 73 00 00 00"
addys.player = "66 0F D6 AB 00 01 00 00 F3 0F 7E 6E 18 66 0F D6 AB 08 01 00 00"
enemies = {}
player = {}
function debugger_onBreakpoint()
if (EIP == addys.enemies) then
enemies[EAX] = {x = readFloat(EAX), y = readFloat(EAX+0x04), z = readFloat(EAX+0x08)}
return 1
end
if (EIP == addys.player) then
for k,v in pairs(enemies) do
print(v)
if (v ~= nil) then
print(EBX) -- this print right here I am wondering about
writeFloat(EBX+player.x, v.x)
writeFloat(EBX+player.y, v.y+1)
writeFloat(EBX+player.z, v.z)
else
enemies.remove(k)
end
end
return 1
end
debug_continueFromBreakpoint(co_run) -- continue execution
end
for k,v in pairs(addys) do
addys[k] = AOBScan(v)
if addys[k] == nil then print("Error: couldnt find AOB " .. v) else addys[k] = tonumber(addys[k][0],16)
end
end
print("Found AOBs")
player.x = 0xFC
player.y = 0x104
player.z = 0x10C
debugProcess()
debug_setBreakpoint(addys.enemies)
debug_setBreakpoint(addys.player) |
that print(EBX) is returning 2 different addresses. My X coordinate locks perfectly on the enemies, but not Y or Z. How could I get the print(EBX) to return 1 address (the correct one). Is it interfering with the other breakpoint?
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Dark Byte
Site Admin
Reputation: 470
Joined: 09 May 2003
Posts: 25788
Location: The netherlands
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| Posted: Thu Aug 29, 2013 3:01 pm Post subject: |
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No, it won't interfere as breakpoints are handled one by one. (the target freezes completely on each breakpoint until the current one continues)
the value of EBX is as it is when EIP has hit that specific address
Most likely the function you're in is called by something else as well. See if you can make a distinction between the correct state and the wrong state
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