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Hard riddle to solve
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Fafaffy
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PostPosted: Sat Aug 04, 2012 11:45 pm    Post subject: Hard riddle to solve Reply with quote
If you're cheating then your IQ is obv. < 5

Now pretend you're watching TV, and you're seeing a show. The show is basically a game show where people do various tasks just for entertainment. Now on this day, there were 100 perfect logistics who came on. Each one was to enter a room and make a circle. Before they entered, a blue or red dot was painted on their forehead. The paint is random, and there is no pattern, and the logistics don't know what the color is.

One thing to note: The logistics don't bring any item into this room, just their body and clothes.

Once all 100 logistics are in the room, and formed a circle, a new thing will happen.

The lights in the room will turn on and off every 20 seconds. If you have a blue dot on your forehead, you must leave the room when the lights are turned off.

Now in this room, there is no form of any kind of communication, all they are allowed to do is look at the other logistics.

After some time, every logistic with a blue dot left the room, and no error was made. How was this possible?

Note: This has a logical answer and isn't something gay as "Oh they looked at a mirror or someones eyes"
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br0l0ck
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PostPosted: Sat Aug 04, 2012 11:53 pm    Post subject: Reply with quote
riddles are stupid
riddles cant have logical answers, thats why they are riddles
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Evil_Intentions
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PostPosted: Sun Aug 05, 2012 12:23 am    Post subject: Reply with quote
Working on it. So don't put the answer OP
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goat69
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PostPosted: Sun Aug 05, 2012 12:26 am    Post subject: Reply with quote
Simple. when nobody else left, they left.
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InternetIsSeriousBusiness
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PostPosted: Sun Aug 05, 2012 12:31 am    Post subject: Reply with quote
42
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Evil_Intentions
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PostPosted: Sun Aug 05, 2012 12:38 am    Post subject: Reply with quote
EasSidezz wrote:
Simple. when nobody else left, they left.


They all think perfectly and in unison though. So by that logic it would go something like this:

FIRST LIGHT:
Observation: Everyone sees 99 people, initial information
Decision: Stay because they have no way of knowing

SECOND LIGHT:
Observation: Nobody has left
Decision: I'll leave then because I must be blue

The game ends, everyone left the room regardless of their color.

You see how that's wrong right?
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InternetIsSeriousBusiness
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PostPosted: Sun Aug 05, 2012 12:55 am    Post subject: Reply with quote
Maybe the color of the light had something to do with it
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Cryoma
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PostPosted: Sun Aug 05, 2012 1:00 am    Post subject: Reply with quote
doesn't say the red dots have to stay, so everyone leaves.
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Simon :v
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PostPosted: Sun Aug 05, 2012 1:08 am    Post subject: Reply with quote
Cryoma wrote:
doesn't say the red dots have to stay, so everyone leaves.

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Cryoma
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PostPosted: Sun Aug 05, 2012 1:09 am    Post subject: Reply with quote
xYashii wrote:
Cryoma wrote:
doesn't say the red dots have to stay, so everyone leaves.


yuno fucking gives me nightmares thanks so much for making her fresh in my mind again
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Evil_Intentions
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PostPosted: Sun Aug 05, 2012 1:31 am    Post subject: Reply with quote
Alright, by a simple rule, a blue will leave after the lights have flicked on the same amount of times as there are other blues[+1]. Let me explain.

Note that one will always ignore a red and only look at blues. So If one sees a Blue and 98 Reds on the 1st light, one expects that Blue to leave if they only see Reds. After the light flicks on the second time, one sees the Blue still there and deduces that that Blue must also see another Blue. Being that there are only 98 Reds, A Blue, and Oneself, both the Blue and one leave.

Note that I use one because this problem works on symmetry. The same thing happens above in the mind of the Blue one sees.

Now if one sees 2 Blues, one would then expect them to leave by[after] the second light due to the logic above. When that doesn't happen, and the third light flashes, one deduces that they are also a blue and then leaves.

So you see how this scales and we get the general rule that One should leave if no blue has left at the x[+1] light flash if there are x blues. This stops a red from leaving because they will always be waiting for one more light than a blue, because they see one extra blue.

EDIT: Those 3 entries in brackets are small edits to improve understanding. The way the flickering works, it was hard to word it properly, but that should do it.
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Cryoma
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PostPosted: Sun Aug 05, 2012 2:11 am    Post subject: Reply with quote
Evil_Intentions wrote:
Alright, by a simple rule, a blue will leave after the lights have flicked on the same amount of times as there are other blues[+1]. Let me explain.

Note that one will always ignore a red and only look at blues. So If one sees a Blue and 98 Reds on the 1st light, one expects that Blue to leave if they only see Reds. After the light flicks on the second time, one sees the Blue still there and deduces that that Blue must also see another Blue. Being that there are only 98 Reds, A Blue, and Oneself, both the Blue and one leave.

Note that I use one because this problem works on symmetry. The same thing happens above in the mind of the Blue one sees.

Now if one sees 2 Blues, one would then expect them to leave by[after] the second light due to the logic above. When that doesn't happen, and the third light flashes, one deduces that they are also a blue and then leaves.

So you see how this scales and we get the general rule that One should leave if no blue has left at the x[+1] light flash if there are x blues. This stops a red from leaving because they will always be waiting for one more light than a blue, because they see one extra blue.

EDIT: Those 3 entries in brackets are small edits to improve understanding. The way the flickering works, it was hard to word it properly, but that should do it.

edit: nvm you're right, I thought they had to get it right on the first try but it says "after some time", didn't read that before.
In other words it's a form on implicit communication, right?
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Evil_Intentions
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PostPosted: Sun Aug 05, 2012 2:16 am    Post subject: Reply with quote
Cryoma wrote:
Evil_Intentions wrote:
Alright, by a simple rule, a blue will leave after the lights have flicked on the same amount of times as there are other blues[+1]. Let me explain.

Note that one will always ignore a red and only look at blues. So If one sees a Blue and 98 Reds on the 1st light, one expects that Blue to leave if they only see Reds. After the light flicks on the second time, one sees the Blue still there and deduces that that Blue must also see another Blue. Being that there are only 98 Reds, A Blue, and Oneself, both the Blue and one leave.

Note that I use one because this problem works on symmetry. The same thing happens above in the mind of the Blue one sees.

Now if one sees 2 Blues, one would then expect them to leave by[after] the second light due to the logic above. When that doesn't happen, and the third light flashes, one deduces that they are also a blue and then leaves.

So you see how this scales and we get the general rule that One should leave if no blue has left at the x[+1] light flash if there are x blues. This stops a red from leaving because they will always be waiting for one more light than a blue, because they see one extra blue.

EDIT: Those 3 entries in brackets are small edits to improve understanding. The way the flickering works, it was hard to word it properly, but that should do it.

edit: nvm you're right, I thought they had to get it right on the first try but it says "after some time", didn't read that before.
In other words it's a form on implicit communication, right?


No, there's no communication, just deduction.
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Cryoma
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PostPosted: Sun Aug 05, 2012 2:22 am    Post subject: Reply with quote
Evil_Intentions wrote:
Cryoma wrote:
Evil_Intentions wrote:
Alright, by a simple rule, a blue will leave after the lights have flicked on the same amount of times as there are other blues[+1]. Let me explain.

Note that one will always ignore a red and only look at blues. So If one sees a Blue and 98 Reds on the 1st light, one expects that Blue to leave if they only see Reds. After the light flicks on the second time, one sees the Blue still there and deduces that that Blue must also see another Blue. Being that there are only 98 Reds, A Blue, and Oneself, both the Blue and one leave.

Note that I use one because this problem works on symmetry. The same thing happens above in the mind of the Blue one sees.

Now if one sees 2 Blues, one would then expect them to leave by[after] the second light due to the logic above. When that doesn't happen, and the third light flashes, one deduces that they are also a blue and then leaves.

So you see how this scales and we get the general rule that One should leave if no blue has left at the x[+1] light flash if there are x blues. This stops a red from leaving because they will always be waiting for one more light than a blue, because they see one extra blue.

EDIT: Those 3 entries in brackets are small edits to improve understanding. The way the flickering works, it was hard to word it properly, but that should do it.

edit: nvm you're right, I thought they had to get it right on the first try but it says "after some time", didn't read that before.
In other words it's a form on implicit communication, right?


No, there's no communication, just deduction.

If the deduction requires knowledge of another person's results of deduction, and that knowledge is provided by their actions or lack thereof, isn't it communication?
It's not like euclidean geometry, it's like... A communal deduction?
idk what to calk it
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Evil_Intentions
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PostPosted: Sun Aug 05, 2012 2:26 am    Post subject: Reply with quote
Cryoma wrote:
Evil_Intentions wrote:
Cryoma wrote:
Evil_Intentions wrote:
Alright, by a simple rule, a blue will leave after the lights have flicked on the same amount of times as there are other blues[+1]. Let me explain.

Note that one will always ignore a red and only look at blues. So If one sees a Blue and 98 Reds on the 1st light, one expects that Blue to leave if they only see Reds. After the light flicks on the second time, one sees the Blue still there and deduces that that Blue must also see another Blue. Being that there are only 98 Reds, A Blue, and Oneself, both the Blue and one leave.

Note that I use one because this problem works on symmetry. The same thing happens above in the mind of the Blue one sees.

Now if one sees 2 Blues, one would then expect them to leave by[after] the second light due to the logic above. When that doesn't happen, and the third light flashes, one deduces that they are also a blue and then leaves.

So you see how this scales and we get the general rule that One should leave if no blue has left at the x[+1] light flash if there are x blues. This stops a red from leaving because they will always be waiting for one more light than a blue, because they see one extra blue.

EDIT: Those 3 entries in brackets are small edits to improve understanding. The way the flickering works, it was hard to word it properly, but that should do it.

edit: nvm you're right, I thought they had to get it right on the first try but it says "after some time", didn't read that before.
In other words it's a form on implicit communication, right?


No, there's no communication, just deduction.

If the deduction requires knowledge of another person's results of deduction, and that knowledge is provided by their actions or lack thereof, isn't it communication?
It's not like euclidean geometry, it's like... A communal deduction?
idk what to calk it


It's just deduction. Period.

World English Dictionary
deduction (dɪˈdʌkʃən)

— n
1. the act or process of deducting or subtracting
2. something, esp a sum of money, that is or may be deducted
3. a. the process of reasoning typical of mathematics and logic, whose conclusions follow necessarily from their premises
b. an argument of this type
c. the conclusion of such an argument
4. logic
a. a systematic method of deriving conclusions that cannot be false when the premises are true, esp one amenable to formalization and study by the science of logic
b. Compare induction an argument of this type

Communication implies that information was transmitted from one source to another by way of the source's actions in some form, this is not the case in the OP.
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