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Is it possible to shorten this code?

 
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gogodr
I post too much
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Joined: 19 Dec 2006
Posts: 2041
PostPosted: Fri Jun 15, 2012 11:27 am    Post subject: Reply with quote
Code:
int a = 0;
for (int i=1;i<=10;i++){
a= i*100000000;
h = 9
if (l < 1000000000-a){
h = 9-i;
}
}


I think
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gogodr
I post too much
Reputation: 125

Joined: 19 Dec 2006
Posts: 2041
PostPosted: Fri Jun 15, 2012 12:02 pm    Post subject: Reply with quote
oh yeah sorry.. the h=9 goes outside of the for loop

Code:

int a = 0;
h = 9
for (int i=1;i<=10;i++){
a= i*100000000;
if (l < 1000000000-a){
h = 9-i;
}
}



I just noticed... why dont you just use integer division?

its

if l is an integer

h = l/100000000

if it is not still do the division and then use the floor function.

your new code is:

Code:
h = l/100000000
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gogodr
I post too much
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Joined: 19 Dec 2006
Posts: 2041
PostPosted: Fri Jun 15, 2012 1:02 pm    Post subject: Reply with quote
the loop will work because outside of the conditions it sets h = 9
if inside the loop the condition is not met (( which is the same as else ))
h is not touched and still 9
but yeah dividing was the best solution.
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Aniblaze
Grandmaster Cheater Supreme
Reputation: 138

Joined: 23 Apr 2006
Posts: 1757
Location: The Netherlands
PostPosted: Fri Jun 15, 2012 1:06 pm    Post subject: Reply with quote
Shrooms wrote:
gogodr wrote:
oh yeah sorry.. the h=9 goes outside of the for loop

Code:

int a = 0;
h = 9
for (int i=1;i<=10;i++){
a= i*100000000;
if (l < 1000000000-a){
h = 9-i;
}
}



I just noticed... why dont you just use integer division?

its

if l is an integer

h = l/100000000

if it is not still do the division and then use the floor function.

your new code is:

Code:
h = l/100000000


my friend on msn stated your code will not work if l is bigger than 900000000

I am now using
Code:

h=l/100000000;
if (h>9) {h=9;}

h = (h>9) ? 9 : h;

If the if-statement bothers you, you can replace it with the ternary operator.
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