Cheat Engine

[JAA149]

Hi All,

I am kind of stuck on the step 6 of the Cheat Engine Tutorial.

1 - Open the Tutorial-i386.
2 - Enter Scan of value 100.
3 - Hit Change value.
4 - Enter the new value in scan.
5 - Get the address 0057C370.
6 - Double click to add to the bottom.
7 - Right Click & "Find What Writes to This Address".
8 - This Attaches the DEbugger.
7 - Hit Chnage Value Again.
8 - I get "00422173 - 89 02 - mov[edx+04],eax"
9 - More information says
>>00422173 - mov [edx+04], eax (Red Color)
With the EDX=002778B0 & EAX=00000148

And herein lies the problem. If I had simply "mov[edx], eax" I would simply put in Hex value of edx=002778B0 and get the address in the main Cheat Engine Found Address. But instaed I have "mov[edx+04], eax"

How do I calculate the value of [edx+04] to put in the Hex value in the main Cheat Engine found Address. I am sure it is a Hexadecimal Addition Calculation but I can't figure out how to do it.

The tutorial says "If the assembler instruction has a calculation (e.g: [esi+12]) at the end then type the value in that's at the end"

So should I do 002778B0+04 ?

Thanks