Cheat Engine

[Fresco]

OK, so there's this double health address.
max hp val = 32 ____ db 00 00 00 00 00 00 40 40
min hp val = 32.0000076591969 ____ db 00 00 40 40 00 00 40 40

I'm trying to make a code that will show the % of health

so 100% would be 32
an 0% __ 32.0000076591969

with what algorithm i could calculate that ?
just need the maths, no assembly. thanks.

[Dark Byte]

again, are you sure it is stored as 32(double) and not as 3 (float/single)?

max hp val looks like 0 - 3
min hp val looks like 3 - 3

(I assume this game stores health as total damage taken and the value behind it is the max amount of damage it can take)

with my method the formula would be:
(maxdamage-damagetaken) / maxdamage * 100
(so: (3-hp) / 3 * 100)

but if you insist it is a double then
(32.0000076591969-hp)/0.0000076591969 * 100

[Fresco]

thank you
you were wright, about the address being a float, even thought i don't know why changing the next address value affects the players health ...
anyways i figured the right algorithm:

[(max_damade - min_damage) * user_%_input / 100] + min_damage

and the assembly would be: