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Getting nil value

 
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bknight2602
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Joined: 08 Oct 2012
Posts: 403

PostPosted: Tue Jan 19, 2016 6:38 pm    Post subject: Getting nil value Reply with quote

Here is a small code
Code:

AL = getAddressList()
if tonumber(memoryrecord_getValue(addresslist_getMemoryRecordByDescription(AL, "Rec 1 Alt Sec Weapon 1st Name"))) >= 131 or
        tonumber(memoryrecord_getValue(addresslist_getMemoryRecordByDescription(AL, "Rec 1 Alt Sec Weapon 1st Name"))) >= 136 and
        tonumber(memoryrecord_getValue(addresslist_getMemoryRecordByDescription(AL, "Rec 1 Alt Sec Weapon 2nd Name"))) >= 0 then
          memoryrecord_setValue(addresslist_getMemoryRecordByDescription(AL, "Rec 1 Alt Sec Weapon Group Num"), 99)
        end

When running I get an error "attempting to compare nil with number"
Now when typing into the debug window
Code:

print(tonumber(memoryrecord_getValue(addresslist_getMemoryRecordByDescription(AL, "Rec 1 Alt Sec Weapon 1st Name"))))
print(tonumber(memoryrecord_getValue(addresslist_getMemoryRecordByDescription(AL, "Rec 1 Alt Sec Weapon 2nd Name"))))

I receive the values of
136
0
These are correct, currently. So why do I get the error?
ETA: The error notification occurs on the first comparison.
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Zanzer
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Joined: 09 Jun 2013
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PostPosted: Tue Jan 19, 2016 7:05 pm    Post subject: Reply with quote

I have no problem executing your script. You sure the problem is there?
I would like to point out that the last two statements in the IF will never evaluate to true and are useless.
Anyway, try changing it up to:
Code:
local AL = getAddressList()
local var1 = tonumber(memoryrecord_getValue(addresslist_getMemoryRecordByDescription(AL, "Rec 1 Alt Sec Weapon 1st Name")))
local var2 = tonumber(memoryrecord_getValue(addresslist_getMemoryRecordByDescription(AL, "Rec 1 Alt Sec Weapon 2nd Name")))
print(var1)
print(var2)
if var1 >= 131 or var1 >= 136 and var2 >= 0 then
  memoryrecord_setValue(addresslist_getMemoryRecordByDescription(AL, "Rec 1 Alt Sec Weapon Group Num"), 99)
end
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bknight2602
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Joined: 08 Oct 2012
Posts: 403

PostPosted: Tue Jan 19, 2016 8:52 pm    Post subject: Reply with quote

Actually the code was not correct as the values were equality instead of an inequality. After setting to == the statements worked without error, but in answer to your question, yes I was getting the error I reported. The error quit happening after the statements were changed to equalities.
Thanks
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