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tanjiajun_34
Grandmaster Cheater
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Location: Singapore
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 Posted: Tue Oct 05, 2010 2:58 am Post subject: Dll Memory Scanner Problems |
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Fixed. Thanks to darkbyte.
Last edited by tanjiajun_34 on Thu Oct 07, 2010 10:58 am; edited 1 time in total |
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Dark Byte
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| Posted: Tue Oct 05, 2010 4:22 am Post subject: |
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try replacing #$70#$7d#$3f#$33#$33#$73#$3f; with #$70#$7d#$3f#$33#$33#$73#$3f#0;
Not sure if delphi adds a 0-terminator at the end of a string build up out of chars
also, when you look at the memory addresses your scanner has found(with ce), do the bytes at least match or are those wrong as well ?
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tanjiajun_34
Grandmaster Cheater
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Joined: 16 Feb 2006
Posts: 786
Location: Singapore
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| Posted: Tue Oct 05, 2010 4:39 am Post subject: |
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Using this...
#$70#$7d#$3f#$33#$33#$73#$3f#0
I search an got an address with aob (using ce to check)
97 06 40 4D 97 06 5C 4D 97 06
the aob i getting is always different...
Without #0
I get an address with he aob 04 01 04 13 04 01 90 19 04 01
the aob i getting is always different too
I am not sure if my displaying of address coding is correct or not.
I just do this...
InttoHex(answer,8)
Update: I found something as well. I view the value in 4 bytes, the found address that my scanner gives starts with the same digits. I tried this on different programs.
Both with and without 0-terminator starts with 129604
Examples...
1296041171
1296041703
1296040962
1296041809
Update 2: Is this memcmp correct?
| Code: | function memcmp(cs,ct:Pointer; count:Cardinal):Integer;
var
su1,su2:PByte;
begin
su1 := cs;
su2 := ct;
while 0 <count do
begin
Result:=su1^-su2^;
if Result <>0 then
Break;
Dec(count);
Inc(su1);
Inc(su2);
end;
end; |
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