Cheat Engine

(\/)_(;,,;)_(\/) · Posted: Mon Oct 12, 2009 4:47 pm Post subject: Need Algebra 2 function help

This is for adding, subtracting, multiplying, and dividing functions. I have these problems I don't understand, could anyone please assist me?

Directions:

"Let f(x) = 3x - 4 and g(x) = x/2 - 5. Find each new function, and state any domain restrictions."

Questions:

28. f + g

29. f - g

30. g - f

31. f o g

32. f/g

33. g/f

Batman · Posted: Mon Oct 12, 2009 6:24 pm Post subject:

Ask your Mom or Dad.

(\/)_(;,,;)_(\/) · Posted: Mon Oct 12, 2009 6:27 pm Post subject:

They aren't good at math and I've had enough stress from them today...I'd rather not go into further explanation on a forum...

NooksCranny · Posted: Mon Oct 12, 2009 6:33 pm Post subject: Re: Need Algebra 2 function help

TrueSoulja · Posted: Mon Oct 12, 2009 6:34 pm Post subject:

Let f(x) = 3x - 4 and g(x) = x/2 - 5

28. F+G

Dude, ignore the f(x) that means nothing just do this get rid of the (x) in front of both of the equations so it`ll be
f=3x - 4
g= x/2 -5

so F+G would be

3x-4 + x/2-5

x/2 would be .5x

3.5x - 9

add 9 to make it

3.5x=9
devide 3.5
x= ? idk.

NooksCranny · Posted: Mon Oct 12, 2009 6:36 pm Post subject:

(\/)_(;,,;)_(\/) · Posted: Mon Oct 12, 2009 6:39 pm Post subject:

Does simplifying it to a decimal truly needed? Because I put them in fractions like for 28 for instance, I put 7x/2 - 9 and none.

NooksCranny · Posted: Mon Oct 12, 2009 6:42 pm Post subject:

(\/)_(;,,;)_(\/) · Posted: Mon Oct 12, 2009 6:57 pm Post subject:

What about g/f for 33?

and 32 would be set up at '2 (3x - 4) / x - 5' wouldn't it?

pkyourface · Posted: Mon Oct 12, 2009 7:02 pm Post subject:

I'm pretty sure all of these are right but I haven't done math in a while so if someone else reading can check and confirm.

Well given that f(x) = 3x -4 and g(x) = x/2 -5 we would simply just plug it in.

28. (3x-4) + (x/2 -5) we can add -4 and -5 so we get (3x + x/2)-9 now we multiply by the common denominator which is 2 and we get 6x/2 + x/2 and final answer is 7x/2 -9

29. Same thing here (3x-4)-(x/2 -5) the negative sign tells us that everything in the follow bracket is negative so I like to change it to an addition equation and we get (3x-4)+(-x/2 +5) and we do what we did before so we can add -4 +5 to get +1 and multiply by a common denominator to get 6x/2 - x/2 which gives us a final answer of 5x/2 +1

30.This one is just like the second equation but reversed so (x/2-5)-(3x-4) change it to an addition equation to get (x/2-5)+(-3x+4) then we can add -5 and 4 to get -1 and we have (x/2)+(-3x), multiply by a common denominator which is 2 to get -6x/2 + x/2 and final answer of -5x/2 -1

31. f o g is like saying "f of g of x" so it looks like f(g(x)) what we do is replace all the "x's" in f(x) with g(x) to get 3(x/2-5)-4 we have to multiply everything in the brackets to get 3x/2 -15 -4 and -15 -4 = -19 for a final answer of 3x/2 -19

32.(f/g)(x) looks like (3x-4)/(x/2 -5) we want to get rid of the x/2 so we multiply everything by 2 which looks like 2(3x-4)/(x-10) and we get a final answer of (6x- Cool

/(x-10)

33. same thing here (g/f)(x) looks like (x/2-5)/(3x-4) and we want to get rid of the x/2 so again we multiply everything by 2 to get 2(x-5)/2(3x-4) then just multiply to get a final answer of (2x-10)/(6x- Cool

I hope this helps a little, remember the best thing to do if you don't understand is to ask your teacher or when class is over stay and ask for help or come in at lunch or afterschool.

EDIT: oops forgot restrictions, 28. none 29. none 30. none 31. none 32. x cannot equal 10 because you can't divide by zero 33. x cannot equal 8/6 because we cannot divide by zero

(\/)_(;,,;)_(\/) · Posted: Mon Oct 12, 2009 7:12 pm Post subject:

@pkyourface

31, I got 3x / 2 - 4
32, I got 6x - 8 / x - 5
33, I got -3 / 3x^2 - 4

Those are the only different final answers I got, would they be wrong?

pkyourface · Posted: Mon Oct 12, 2009 7:17 pm Post subject:

Well for 31. You have to multiply x/2 by 3 and -5 by 3 also because it is in the bracket which gives you 3x/2 -15 -4 which adds up to 3x/2-19

32. Again you have to multiply everything in the bracket by 2 so 2(x/2-5) is x - 10 not x-5

33. Im not sure let me redo it and see what I get, also explaining the steps that you took to get those answers will help in finding out what you did wrong.

Edit: 33. im not sure how you got a power could you write out the steps you took to get that answer?

(\/)_(;,,;)_(\/) · Posted: Mon Oct 12, 2009 7:26 pm Post subject:

I'm actually not even sure about 33, I got the answer from a friend who's in Calc in college and he's not respond at the moment... What did you get for 33 as far as your steps if they were wrong or right the first time.

pkyourface · Posted: Mon Oct 12, 2009 7:34 pm Post subject:

Hmm im not quite sure how you would get a power and the right answer for 32. is actually (x-10)/(6x- Cool

not (2x-10)/(6x- Cool

does it have answers in the back of the book that you can check with? I think he might have got the power from flipping x/2 to 2/x then multiplying but I'm not sure if your supposed to do that.

(\/)_(;,,;)_(\/) · Posted: Mon Oct 12, 2009 7:47 pm Post subject:

Sadly, there isn't a back it was a worksheet. And he probably did flip them, he left but he said it was a long explanation to not do it in person but I do recall him saying he flipped.