Cheat Engine

Drkgodz · Posted: Sat Jun 13, 2009 5:23 pm Post subject: A Math Question

Say I have a line with the equation of 2X+4. I know the distance of the line is 50. How would I get how much the width is(w/o graphing)? In other words, how could I see how much the X value changes in the distance of 50.

hacksign23 · Posted: Sat Jun 13, 2009 5:37 pm Post subject:

okay
so you need the distance formula
sqrt((x1-x2)^2 + (y1-y2)^2)

so then

sqrt((x1-x2)^2 + (y1-y2)^2) = 50

2x + 4 =
x + 2
m = 1, y-intercept = 2

so...
(0,2)

and you wanna input it in

sqrt(x^2 + y^2*4) = 50

or something... i think i failed D;

SoccaBallDude · Posted: Sat Jun 13, 2009 5:45 pm Post subject:

Cos 45° = w/50
w = 50(Cos 45°)
w ≈ 35.36

Peen! · How do I cheat? Reputation: 0 Joined: 04 Jun 2009 Posts: 5

SoccaBallDude · Posted: Sun Jun 14, 2009 10:23 am Post subject:

Sorry, I don't know why I did that.

Arctan x° = 2/1
x° = Arctan(2/1)

Cos Arctan(2/1)° = w/50
w = 50(Cos Arctan(2/1)°)
w ≈ 22.36