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Array storage in Memory

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Anden100
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Posted: Thu Mar 19, 2009 2:34 pm Post subject: Array storage in Memory

When you make an Integer value, lets for instance take 133337, it will be stored in the memory as the following:

Code:

D9 08 02 00

because 133337dec = 000208D9hex, and backwards

But what if i took an array of ints, lets say

Code:

int var[2] = {133337, 1333337, 13333337};

How would it be stored then?, like this?:

Code:

var[0] var[1] var[2]
D9 08 02 00 59 58 14 00 59 73 CB 00

Or how would it be stored?

samuri25404
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Posted: Thu Mar 19, 2009 2:36 pm Post subject:

Yeah.

The way the compiler accesses the location of an index of an array is with this simple algorithm:

Code:

Location = ArrayBase + Index * sizeof( DataType )

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Anden100
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Posted: Thu Mar 19, 2009 3:14 pm Post subject:

samuri25404 wrote:

Yeah.

The way the compiler accesses the location of an index of an array is with this simple algorithm:

Code:

Location = ArrayBase + Index * sizeof( DataType )

So, if var was located at 00400000 accessing var[2], where var is an array of integers, it would be at 0040000C?

smartz993
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Posted: Thu Mar 19, 2009 3:20 pm Post subject:

Anden100 wrote:

samuri25404 wrote:

Yeah.

The way the compiler accesses the location of an index of an array is with this simple algorithm:

Code:

Location = ArrayBase + Index * sizeof( DataType )

So, if var was located at 00400000 accessing var[2], where var is an array of integers, it would be at 0040000C?

No, it would be 00400008.

1st integer = 00400000 = var[0]
2nd integer = 00400004 = var[1]
3rd integer = 00400008 = var[2]

&Vage
Grandmaster Cheater Supreme

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Joined: 25 Jul 2008
Posts: 1053

Posted: Thu Mar 19, 2009 3:31 pm Post subject:

smartz993 wrote:

Anden100 wrote:

samuri25404 wrote:

Yeah.

The way the compiler accesses the location of an index of an array is with this simple algorithm:

Code:

Location = ArrayBase + Index * sizeof( DataType )

So, if var was located at 00400000 accessing var[2], where var is an array of integers, it would be at 0040000C?

No, it would be 00400008.

1st integer = 00400000 = var[0]
2nd integer = 00400004 = var[1]
3rd integer = 00400008 = var[2]

What if the variables were WORD or BYTE ;O

smartz993
I post too much

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Joined: 20 Jun 2006
Posts: 2013
Location: USA

Posted: Thu Mar 19, 2009 3:38 pm Post subject:

S3NS4 wrote:

smartz993 wrote:

Anden100 wrote:

samuri25404 wrote:

Yeah.

The way the compiler accesses the location of an index of an array is with this simple algorithm:

Code:

Location = ArrayBase + Index * sizeof( DataType )

So, if var was located at 00400000 accessing var[2], where var is an array of integers, it would be at 0040000C?

No, it would be 00400008.

1st integer = 00400000 = var[0]
2nd integer = 00400004 = var[1]
3rd integer = 00400008 = var[2]

What if the variables were WORD or BYTE ;O

WORD = 2 bytes
BYTE = 1 byte

so add respectively

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