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Micah
Grandmaster Cheater
 Reputation: 1
Joined: 30 Mar 2007
Posts: 833
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 Posted: Sat Feb 07, 2009 1:20 pm Post subject: Attempting VB 2008 |
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I have been playing around with VB 2008 lately, trying to make an application for my dad.
I am not really familiar with it at all.
The application I am trying to make is supposed to generate a number using 5 different groups of numbers.
EG
The first number chosen would be 25, the second would be 14, the third would be 7, the fourth would be 55, and the 5th would be 34.
So the program would output 251475534
Here is what I have so far.
| Code: | Private Sub Button1_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles Button1.Click
Dim LoopNumbr As Integer
Dim Rnd As New Random
Dim RAN As Integer
Dim LotteryCol1(7) As String
LotteryCol1(0) = "7"
LotteryCol1(1) = "9"
LotteryCol1(2) = "12"
LotteryCol1(3) = "17"
LotteryCol1(4) = "20"
LotteryCol1(5) = "23"
LotteryCol1(6) = "24"
LotteryCol1(7) = "25"
LoopNumbr = LoopNum.Text
If LoopNumbr = 0 Then LoopNumbr = 1
Do While LoopNumbr > 0
RAN = Rnd.Next(LotteryCol1(0), LotteryCol1(7))
ListBox1.Items.Add(RAN.ToString)
LoopNumbr = LoopNumbr - 1
Loop |
This should display randomly, a number from the list of numbers, but unfotunately, that doesnt happen. What it does is it displace a number between 7 and 25.
Is it possible for it to choose only those numbers, and not in between?
Thanks for reading.
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XTrinityX
Expert Cheater
 Reputation: 0
Joined: 18 May 2006
Posts: 123
Location: Connecticut
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| Posted: Sat Feb 07, 2009 3:44 pm Post subject: |
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You want to generate a random index of your array of integers and use that index to retrieve your value.
| Code: |
RAN = Rnd.Next(0, 8) //Generate number between 0 and 7, inclusive.
ListBox1.Items.Add(LotteryColl(RAN))
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Micah
Grandmaster Cheater
Reputation: 1
Joined: 30 Mar 2007
Posts: 833
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| Posted: Sat Feb 07, 2009 6:07 pm Post subject: |
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Thanks! I had something like that, but it was different, so it didn't work!
+Rep once I try this.
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