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CEF's private tutor
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SGL
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PostPosted: Thu Oct 09, 2008 9:35 pm    Post subject: CEF's private tutor Reply with quote

I will teach you how to substract and how to add.
I can do you homework also.

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[SPW]Jsin
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PostPosted: Thu Oct 09, 2008 9:37 pm    Post subject: Reply with quote

1 + 1 - 1=
???

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Thanh
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PostPosted: Thu Oct 09, 2008 9:37 pm    Post subject: Re: CEF's private tutor Reply with quote

SirGodlike wrote:
I will teach you how to substract and how to add.
I can do you homework also.


Okay.

Do you accept Pre-Calculus?
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SGL
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PostPosted: Thu Oct 09, 2008 9:40 pm    Post subject: Re: CEF's private tutor Reply with quote

Tawn<3 wrote:
SirGodlike wrote:
I will teach you how to substract and how to add.
I can do you homework also.


Okay.

Do you accept Pre-Calculus?

Of course.

@jsin95
The answer is 1.

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[SPW]Jsin
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PostPosted: Thu Oct 09, 2008 9:42 pm    Post subject: Re: CEF's private tutor Reply with quote

SirGodlike wrote:
Tawn<3 wrote:
SirGodlike wrote:
I will teach you how to substract and how to add.
I can do you homework also.


Okay.

Do you accept Pre-Calculus?

Of course.

@jsin95
The answer is 1.


*claps vigorously*

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Thanh
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PostPosted: Thu Oct 09, 2008 9:44 pm    Post subject: Reply with quote

f(x) = f(x-h) - f(x^2) over h
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AverageAzn247
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PostPosted: Thu Oct 09, 2008 9:45 pm    Post subject: Reply with quote

Tawn<3 wrote:
f(x) = f(x-h) - f(x^2) over h
wut do u want to do?
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elpacco
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PostPosted: Thu Oct 09, 2008 9:47 pm    Post subject: Reply with quote

Tawn<3 wrote:
f(x) = f(x-h) - f(x^2) over h
thats not precalc
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Thanh
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PostPosted: Thu Oct 09, 2008 9:47 pm    Post subject: Reply with quote

averageazn247 wrote:
Tawn<3 wrote:
f(x) = f(x-h) - f(x^2) over h
wut do u want to do?


I don't know exactly. Find h? or solve it? eh
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AverageAzn247
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PostPosted: Thu Oct 09, 2008 9:48 pm    Post subject: Reply with quote

Tawn<3 wrote:
averageazn247 wrote:
Tawn<3 wrote:
f(x) = f(x-h) - f(x^2) over h
wut do u want to do?


I don't know exactly. Find h? or solve it? eh
It should ask u graph/simply, find zeros or something.
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Icklorfin
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PostPosted: Thu Oct 09, 2008 9:49 pm    Post subject: Reply with quote

damn............FUUUUUUUUUCK
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Thanh
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PostPosted: Thu Oct 09, 2008 9:49 pm    Post subject: Reply with quote

averageazn247 wrote:
Tawn<3 wrote:
averageazn247 wrote:
Tawn<3 wrote:
f(x) = f(x-h) - f(x^2) over h
wut do u want to do?


I don't know exactly. Find h? or solve it? eh
It should ask u graph/simply, find zeros or something.


Nope. Find the different quotient.
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SGL
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PostPosted: Thu Oct 09, 2008 9:54 pm    Post subject: Reply with quote

Tawn<3 wrote:
f(x) = f(x-h) - f(x^2) over h

h=1

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Thanh
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PostPosted: Thu Oct 09, 2008 9:55 pm    Post subject: Reply with quote

SirGodlike wrote:
Tawn<3 wrote:
f(x) = f(x-h) - f(x^2) over h

h=1


Woops, I didn't finish writing the equation

f(x) = 5 - 6x + x^2, f(x-h) - f(x^2) over h


Last edited by Thanh on Thu Oct 09, 2008 9:56 pm; edited 1 time in total
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AverageAzn247
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PostPosted: Thu Oct 09, 2008 9:56 pm    Post subject: Reply with quote

w8 was the orginal problem (x-x^2)/h?
And then u substitiuded x-h ?

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