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C++ dec in hex(no converting, need the same numbers in hex)

 
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redhead
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PostPosted: Tue Sep 30, 2008 9:17 am    Post subject: C++ dec in hex(no converting, need the same numbers in hex) Reply with quote
Here was a dumb question, please ignore.
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&Vage
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PostPosted: Tue Sep 30, 2008 7:15 pm    Post subject: Reply with quote
DWORD lolwat;

sprintf(lolwat, "%X08", 9048093);


Not possible without conversion...
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GMZorita
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PostPosted: Tue Sep 30, 2008 7:18 pm    Post subject: Re: C++ dec in hex(no converting, need the same numbers in h Reply with quote
redhead wrote:
Here was a dumb question, please ignore.

You mean like a string?
String num = 7A;
num = "0x"+num;
Because the title looks like.
same number in hex?
either you want
10 = 0x10
or 10 = 0xC


Depends on the usage, you wan't to output it?
Use IntToHex((int)IntGoesHere,8);
Eg. IntToHex((int)485025,8); returns = "000766A1"
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Noz3001
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PostPosted: Wed Oct 01, 2008 3:54 am    Post subject: Reply with quote
Code:
std::cout << std::hex << 69;


Mr. Green
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redhead
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PostPosted: Wed Oct 01, 2008 6:33 am    Post subject: Re: C++ dec in hex(no converting, need the same numbers in h Reply with quote
GMZorita wrote:
redhead wrote:
Here was a dumb question, please ignore.

You mean like a string?
String num = 7A;
num = "0x"+num;
Because the title looks like.
same number in hex?
either you want
10 = 0x10
or 10 = 0xC


Depends on the usage, you wan't to output it?
Use IntToHex((int)IntGoesHere,Cool;
Eg. IntToHex((int)485025,Cool; returns = "000766A1"


I wanted 10 = 0x10 (or 10 = 16).
But it doesn't matter anymore, I found some mistakes on my calculating and I don't need that anymore.^^
Thx anyway
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