Cheat Engine

lurc · Posted: Tue Apr 22, 2008 3:39 pm Post subject:

0x4B is most likely a packet start. It handles summonbag's

getInt() most likely gets the Integer value from the packet in the array of bytes defined in the function.

this? probly the chosen player. Your most likely switching buf for cases and, and its adding 2 to the buf and then calling the function from the class "Mob"; handleSummonBag(..);

So your switching the packet, if its first byte is 0x4B then handleSummonBag to the chosen player and the byte is the 3rd byte in the array. They are now getting the itemID from the 8th packet (because they had already added 2 to the packet when calling the function, so +6 = 8, +6 is probly there because the item id is located at the 8th byte in the array ) then checking which summon bag was called. Finally it spawn's the mob depending on the itemID.

"Inventory::takeItem(player, itemID, 1);" this is most likely the thing that deletes the item from your inventory.
My guess is that the first parameter is the chosen player, the second is obviously the itemID of the item, and the third parameter is the quanitity.

Hope that helps.

kopelito · Posted: Tue Apr 22, 2008 4:10 pm Post subject:

I have only one thing to say.

THANK YOU SOOO MUCH.

rep for you.

atom0s · Posted: Tue Apr 22, 2008 5:48 pm Post subject:

Google'd a bit showed this is code from a Maple server.

Symbol · Posted: Wed Apr 23, 2008 3:49 am Post subject:

Why is there "default: break;"? Confused

And isn't it supposed to summon a few monsters? not only one? I'd just create an xml file with the sack ID and add boolean value "IsSummonSack" and the monsters it summon and chance and then just
if (Drops[something]::IsSummonSack)
{
int rand;
for (int i = 0; i < Drops[something]::Monsters.size(); i++){
rand = rand() & Drops[something]::Monsters[i]->Chance;
for (;rand > 0; rand--)
spawnMob(player, Drops[something]::Monsters[i])
}

Something like this... instead of making a really big switch. (or like you're doing, if else...)

lurc · Posted: Wed Apr 23, 2008 7:47 am Post subject:

he most likely only showed a couple of the spawns's which were bosses.

default: break; just means if none apply break out (just in case)

Symbol · Posted: Wed Apr 23, 2008 4:56 pm Post subject:

I know what default: break does, just saying, isn't it usless? switch is like lots of "if"'s:
case 0:
case 1:
case 2:
default:

would look like: (eax = 2)
cmp eax,2
jnz case 1
case 2:
bla bla
jmp out
dec eax
jnz case 0
case 1:
bla bla
jmp out
case 0:
bla bla
jmp out

out:
default:
bla bla
ret

or in this case:
default:
ret

So without default, you can imagine how it will look like.

hcavolsdsadgadsg · Posted: Wed Apr 23, 2008 8:01 pm Post subject:

yes, it wouldn't matter if it hit default, if it got that far it would just fall through.