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Aniblaze
Grandmaster Cheater Supreme
 Reputation: 138
Joined: 23 Apr 2006
Posts: 1757
Location: The Netherlands
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 Posted: Fri Aug 21, 2015 5:07 pm Post subject: |
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| HackOtaku wrote: | oh, lol, I named $item as an array, then as the return object.
I changed it to $itemAr, but the issue is that
$itemAr[$j] = $item["name"];
when I attempt that, it tells me "name" is an illegal string offset, even though I can see the data in front of me. |
It looks like the API you're talking to returns the data in JSON format. You'd need to use json_decode() first, and then use it as an object (e.g. $data->name).
EDIT: Also might I recommend installing and using xdebug on your dev machine? using print_r() or var_dump() is making it unnecessarily difficult for you to debug your code.
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HackOtaku
I posted the 500000th topic
 Reputation: 81
Joined: 31 May 2007
Posts: 228
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| Posted: Fri Aug 21, 2015 6:21 pm Post subject: |
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| Aniblaze wrote: | | HackOtaku wrote: | oh, lol, I named $item as an array, then as the return object.
I changed it to $itemAr, but the issue is that
$itemAr[$j] = $item["name"];
when I attempt that, it tells me "name" is an illegal string offset, even though I can see the data in front of me. |
It looks like the API you're talking to returns the data in JSON format. You'd need to use json_decode() first, and then use it as an object (e.g. $data->name).
EDIT: Also might I recommend installing and using xdebug on your dev machine? using print_r() or var_dump() is making it unnecessarily difficult for you to debug your code. |
ding ding. This solved everything and it all works now, thanks! And I will definitely be using xdebug in future php works.
Unfortunately, the person I am working with decided he doesn't much like php, and wants to do it all in javascript instead, lol.
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atom0s
Moderator
 Reputation: 205
Joined: 25 Jan 2006
Posts: 8588
Location: 127.0.0.1
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| Posted: Fri Aug 21, 2015 10:21 pm Post subject: |
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If you move to nodejs you'll enjoy it. It is a very nice toolset to work with.
_________________
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