Cheat Engine

[dnsi0]

Yea as long as the point is understood.

[Uzeil]

If you're getting into assembler/byte analyzation, thinking add [eax],eax might be a 0'd out variable - is a simple no-no.



The whole answer to this thread: 90 90 90 90 isn't held in 1 byte, as it's 4 bytes. What it's stating is that, starting from that address, the sequence of bytes is 90 90 90 90 - which means that that address accounts for the first 90, the next is the next 90, then the one after that is the next, and the one ater that is the next. Conclusion: That address and the three after it all have the byte value of 0x90(0x_ _ = hexadecimal. It's a C thing. $90 in Delphi)

And, for additional information(which yuo already know), 0x90 = NOP - meaning something to do nothing.


And I don't think it's more important to understand the answer to the original question than it is to maintain correct information in other fields.

[dnsi0]

But here is my question:

How do I write to each of these bytes or read from them?

[samuri25404]

You don't write to the bytes, you write to the address, as with the reading.

If you want to write bytes to an address, use WriteProcessMemory.

[Uzeil]

Defined "read" and "write"


From another process?
Just understand them?
In a CE AA script?