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LeechBR
How do I cheat?
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Joined: 05 Dec 2019
Posts: 1
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 Posted: Thu Dec 05, 2019 3:12 pm Post subject: how does Adding Offsets Works? |
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Hey Guys I'm Trying to learn more about CE Pointers.
I want to know how the adding offsets works. Example That CE shows me:
BASE ADRESS = 00792E70 + Offset 468 = 00BAC248
how is That possible?
In hex Calculator I get: 7932D8
I need to understand how does this adding works plz can some one explain me?
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Csimbi
I post too much
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Joined: 14 Jul 2007
Posts: 3110
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| Posted: Thu Dec 05, 2019 3:34 pm Post subject: |
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Did you go through the tutorial that ships with CE?
I'd highly recommend it.
You can cheat the tutorial with this.
This will help understanding pointers.
Hint: in your first one you seem to be dealing with an actual pointer, in your second one you clearly have an address.
People can come here, go through the trouble of registering with even trying to search for cheat engine pointer tutorial on google...
I am not surprised this planet is circling the drain...
People, God gave you a brain, use it!
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DanyDollaro
Master Cheater
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Joined: 01 Aug 2019
Posts: 334
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| Posted: Thu Dec 05, 2019 4:34 pm Post subject: |
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What you say is correct "0x792E70 + 0x468 = 0x7932D8" but in your case you are talking about a multilevel pointer, so it is a pointer that points to a pointer up to the desired value, i highlight the word "pointer that points to a pointer" because it is true that "0x792E70 + 0x468 = 0x7932D8" but what you see in Cheat Engine is something like: | Code: | | [0x792E70 + 0x468] -> 00BAC248 |
in assembly the square brackets "[]" indicate that it is a pointer, also the character "->" is used in many programming languages to indicate a pointer, so the expression is completed as follows:
| Code: | [0x792E70 + 0x468] -> 00BAC248
[0x7932D8] -> 00BAC248
00BAC248 = 00BAC248 |
now if you go to see in the memory location pointed to by 0x7932D8 you will find the value 0xBAC248 because it is the case of a pointer pointing to a pointer
Note: in the Memory view the characters are written in little endian therefore on the pointed region from 0x7932D8 you will find this: 48 C2 BA 00
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