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What this code means?

 
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omeleterice
How do I cheat?
Reputation: 0

Joined: 27 Jul 2019
Posts: 3

PostPosted: Tue Jul 30, 2019 5:31 am    Post subject: What this code means? Reply with quote

Im very newbie at CE and pls forgive me for not reading rules for my previous topic. Now there this code:
Original:
Code:
alloc(newmem,2048)
label(returnhere)
label(originalcode)
label(exit)

newmem: //this is allocated memory, you have read,write,execute access
//place your code here

originalcode:
movd xmm1,[ebx+00]

exit:
jmp returnhere

19A5A7D9:
jmp newmem
returnhere:


modified:
Code:

alloc(newmem,2048)
label(returnhere)
label(originalcode)
label(exit)

newmem: //this is allocated memory, you have read,write,execute access
//place your code here
mov [ebx+00],(float)0
originalcode:
movd xmm1,[ebx+00]

exit:
jmp returnhere

19A5A7D9:
jmp newmem
returnhere:


This code use to be no recoil for guns but it doesnt do that anymore but still helpful. the modified version only add this line "mov [ebx+00],(float)0" below "//place your code here" . What does it means and could it be save as lua script or cheat table?
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FreeER
Grandmaster Cheater Supreme
Reputation: 53

Joined: 09 Aug 2013
Posts: 1091

PostPosted: Tue Jul 30, 2019 8:12 am    Post subject: Reply with quote

it changes the float at the address stored in ebx to 0.
_________________
https://github.com/FreeER/ has a few CE related repos
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omeleterice
How do I cheat?
Reputation: 0

Joined: 27 Jul 2019
Posts: 3

PostPosted: Tue Jul 30, 2019 9:36 am    Post subject: Reply with quote

The code executed by going auto-assembly-->code injection, then the codes pop-up. Is there any way to shorten the steps so that I dont need to scan the AOB then testing the address 1 by 1?
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