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Parsing / Split File Name From a URL (%20 space)

 
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Corroder
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PostPosted: Mon Apr 23, 2018 11:21 pm    Post subject: Parsing / Split File Name From a URL (%20 space) Reply with quote

Hi there,

Code:
url = 'http://link.planetlagu.site/save/01%20Rich%20Chigga%20Glow%20Like%20Dat.mp3'
fn = url:match( "([^/]+)$" )

print(fn)
-- result = 01%20Rich%20Chigga%20Glow%20Like%20Dat.mp3

fn = string.gsub(fn, "%20", " ")
-- result = invalid capture index %2   



So i try to parsing mp3 file name from a mp3 url. But as shown on code block above I am facing problem with this '%20 (space character)' as invalid index. I want result as : '01 Rich Chingga Glow Like Dat.mp3'.
Any solution ?. Thank you

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FreeER
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PostPosted: Tue Apr 24, 2018 5:27 am    Post subject: Reply with quote

% is the formatting character used in lua's pattern matching eg. %d is a digit character, use %% to escape it.

20 is the hex value for space, I know there are other % encodings that are possible, if they're all the same then you could use this to handle all of them
Code:
fn = string.gsub(fn, "%%(%x%x)", function(cap) return string.char(tonumber(cap,16)) end)

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Corroder
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PostPosted: Tue Apr 24, 2018 9:04 am    Post subject: Reply with quote

Thanks @freeER

Your code :

Code:
url = 'http://link.planetlagu.site/save/01%20Rich%20Chigga%20Glow%20Like%20Dat.mp3'
fn = url:match( "([^/]+)$" )

fn = string.gsub(fn, "%%(%x%x)", function(cap) return string.char(tonumber(cap,16)) end)
-- result = 01 Rich Chingga Glow Like Dat.mp3


Anyway, I found a general function from garrysmod/garrysmod/lua/includes/extensions/string.lua with has function
to find and replace any character in a URL.

Code:
function explode(separator, str, withpattern)
   if ( withpattern == nil ) then withpattern = false end
   local ret = {}
   local current_pos = 1
   for i = 1, string.len( str ) do
      local start_pos, end_pos = string.find( str, separator, current_pos, not withpattern )
      if ( not start_pos ) then break end
      ret[ i ] = string.sub( str, current_pos, start_pos - 1 )
      current_pos = end_pos + 1
   end
   ret[ #ret + 1 ] = string.sub( str, current_pos )
   return ret
end

function replace( str, tofind, toreplace )
   local tbl = explode( tofind, str )
   if ( tbl[ 1 ] ) then return table.concat( tbl, toreplace ) end
   return str
end

url = 'http://link.planetlagu.site/save/01%20Rich%20Chigga%20Glow%20Like%20Dat.mp3'
fn = url:match( "([^/]+)$" )
print(replace(fn, "%20", " "))    --- result = 01 Rich Chigga Glow Like Dat.mp3

fn1 = replace(url, "%20", " ")
fn1 = replace(fn1, "//", " ")
print(replace(fn1, "/", " "))   --- result = http: link.planetlagu.site save 01 Rich Chigga Glow Like Dat.mp3

-- and so on...

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