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		| eranj How do I cheat?
 
 ![]() Reputation: 0 
 Joined: 28 Feb 2010
 Posts: 9
 
 
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				|  Posted: Fri Mar 12, 2010 5:55 pm    Post subject: How to combine two codes and how to make them shorter... |   |  
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				| I made Auto Level Up cheat for World Of Goo and i Have two parts. this one:
 
  	  | Code: |  	  | [ENABLE] //code from here to '[DISABLE]' will be used to enable the cheat
 alloc(newmem,2048) //2kb should be enough
 label(returnhere)
 label(originalcode)
 label(exit)
 
 00411A51:
 jmp newmem
 nop
 returnhere:
 
 newmem: //this is allocated memory, you have read,write,execute access
 
 
 
 originalcode:
 mov [esi+000000b8],0000001F4
 nop
 
 exit:
 jmp returnhere
 
 
 
 [DISABLE]
 //code from here till the end of the code will be used to disable the cheat
 dealloc(newmem)
 00411A51:
 mov [esi+000000b8],ebx
 //Alt: db 89 9E B8 00 00
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 and this one:
 
 
  	  | Code: |  	  | [ENABLE] //code from here to '[DISABLE]' will be used to enable the cheat
 alloc(newmem,2048) //2kb should be enough
 label(returnhere)
 label(originalcode)
 label(exit)
 
 0045DCC1:
 jmp newmem
 nop
 returnhere:
 
 newmem: //this is allocated memory, you have read,write,execute access
 //place your code here
 
 
 originalcode:
 mov eax,00000001
 mov [edi+000000b4],eax
 
 exit:
 jmp returnhere
 
 
 
 [DISABLE]
 //code from here till the end of the code will be used to disable the cheat
 dealloc(newmem)
 0045DCC1:
 mov [edi+000000b4],eax
 //Alt: db 89 87 B4 00 00
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 How can I make them shorter and combine them into one code?
 Every time I try to change the code (cut stuff) or combine one with the other, the program just ends...
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		| eranj How do I cheat?
 
 ![]() Reputation: 0 
 Joined: 28 Feb 2010
 Posts: 9
 
 
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				|  Posted: Wed Mar 24, 2010 11:16 am    Post subject: |   |  
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				| 146 views and no replay? i dont think its that hard :/
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		| Slugsnack Grandmaster Cheater Supreme
 
 ![]() Reputation: 71 
 Joined: 24 Jan 2007
 Posts: 1857
 
 
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				|  Posted: Thu Apr 08, 2010 9:55 am    Post subject: |   |  
				| 
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				| don't know if you still want this. 
 
  	  | Code: |  	  | [ENABLE] alloc(newmem,32)
 label(returnhere)
 
 00411A51:
 jmp newmem
 nop
 returnhere:
 
 newmem: //this is allocated memory, you have read,write,execute access
 
 mov [esi+000000b8],0000001F4
 nop
 jmp returnhere
 
 
 [DISABLE]
 //code from here till the end of the code will be used to disable the cheat
 dealloc(newmem)
 00411A51:
 mov [esi+000000b8],ebx
 //Alt: db 89 9E B8 00 00
 | 
 
 
  	  | Code: |  	  | [ENABLE] //code from here to '[DISABLE]' will be used to enable the cheat
 alloc(newmem,32)
 label(returnhere)
 
 0045DCC1:
 jmp newmem
 nop
 returnhere:
 
 newmem: //this is allocated memory, you have read,write,execute access
 
 mov eax,00000001
 mov [edi+000000b4],eax
 jmp returnhere
 
 
 
 [DISABLE]
 //code from here till the end of the code will be used to disable the cheat
 dealloc(newmem)
 0045DCC1:
 mov [edi+000000b4],eax
 //Alt: db 89 87 B4 00 00
 | 
 
 didn't change much except allocation size to something more appropriate and also got rid of some labels that are not needed. the resulting code itself is the same though.
 
 then to combine..
 
 
  	  | Code: |  	  | [ENABLE] alloc(newmem,32)
 alloc(newmem2,32)
 label(returnhere)
 label(returnhere2)
 
 00411A51:
 jmp newmem
 nop
 returnhere:
 
 0045DCC1:
 jmp newmem2
 nop
 returnhere2:
 
 newmem: //this is allocated memory, you have read,write,execute access
 
 mov [esi+000000b8],0000001F4
 nop
 jmp returnhere
 
 
 newmem2: //this is allocated memory, you have read,write,execute access
 
 mov eax,00000001
 mov [edi+000000b4],eax
 jmp returnhere2
 
 
 [DISABLE]
 //code from here till the end of the code will be used to disable the cheat
 dealloc(newmem)
 dealloc(newmem2)
 00411A51:
 mov [esi+000000b8],ebx
 //Alt: db 89 9E B8 00 00
 
 0045DCC1:
 mov [edi+000000b4],eax
 //Alt: db 89 87 B4 00 00
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 you might even be able to combine those memory allocation/deallocations.
 
 
  	  | Code: |  	  | [ENABLE] alloc(newmem,64)
 label(newmem2)
 label(returnhere)
 label(returnhere2)
 
 00411A51:
 jmp newmem
 nop
 returnhere:
 
 0045DCC1:
 jmp newmem2
 nop
 returnhere2:
 
 newmem: //this is allocated memory, you have read,write,execute access
 
 mov [esi+000000b8],0000001F4
 nop
 jmp returnhere
 
 newmem2: //this is the same block of allocated memory, this injected piece of code is directly after the first one
 
 mov eax,00000001
 mov [edi+000000b4],eax
 jmp returnhere2
 
 
 [DISABLE]
 //code from here till the end of the code will be used to disable the cheat
 dealloc(newmem)
 
 00411A51:
 mov [esi+000000b8],ebx
 //Alt: db 89 9E B8 00 00
 
 0045DCC1:
 mov [edi+000000b4],eax
 //Alt: db 89 87 B4 00 00
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