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kinoshin How do I cheat?
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Joined: 17 Sep 2006 Posts: 0
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Posted: Sun Sep 24, 2006 7:29 am Post subject: NEED HELP ON STEP 8!!! |
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hi guys..i am quite new to this and does not know much about hacking and the tutorial until step 7 i am still able to cope with it but as for step 8 i am stuck after finding the 2nd pointer and beyond that when i use the address of the 2nd value i found and scan it, it shows no result and i am stucked...i do not know whether i am doing the right steps so if any of you guys can post a tutorial on step 8 it will be very helpful to mi... can???
for example the address for the health i have found and found the lvl 1 pointer and after that i use the address of the pointer to find the next address and continues... but after i found two pointers..no more results shown after i follow the steps i used...and i guess i have done something wrong..
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Glest Master Cheater
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Joined: 12 Jul 2006 Posts: 334 Location: The Netherlands
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Posted: Sun Sep 24, 2006 9:50 am Post subject: |
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screenie please.. or password... Don't want to start all over again (lazy)...
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me Grandmaster Cheater
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Joined: 24 Jun 2004 Posts: 733 Location: location location
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Posted: Sun Sep 24, 2006 9:43 pm Post subject: |
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well the password is 525927 for level 8,
if you put a breakpoint "FIND OUT WHAT WRITES TO THIS ADDRESS" on your first address you will get an address with
MOV [EAX+18],ESI
in the more info window you will see eax has the value of the pointer to search for, just tick the HEX BOX and type in the exact value for whats in EAX, then add the address you find to the code list and hit the put a "FIND OUT WHAT ACCESSES THIS ADDRESS" breakpoint on the new address, you just keep this up till you find the static base pointer,
now lets cheat a bit , lets cheat the cheat engine tutorial
if you look above the code line you found first of all MOV [EAX+18],ESI
, just scroll up a few lines so you get this little lot
MOV EAX,[0045CC18] <<---- wonder if this is the static pointer
MOV EAX,[EAX+0C] <<-----pointer with offset C
MOV EAX,[EAX+14] <<-----pointer with offset 14
MOV EAX,[EAX] <<-----pointer with zero offset
MOV EAX,[EAX+18] <<------first pointer we found with the "FIND OUT WHAT ACCESSES THIS ADDRESS" breakpoint
you can even right click these addresses and use the "FIND OUT WHAT ADDRESSES THIS CODE READS FROM " option,
anyhow you start by freezing the base pointer [45cc18]
then the other addresses with their offsets,
and then make sure you got 5000 in your first found address all frozen then hit the change pointer button,
if you want to do it properly though you will need to go into cheat engine settings/ code finder tab/ and change from debug registers >> to >> "MEMORY ACCESS EXEPTIONS",
its best to start ce change the code finder settings and restart ce, maybe even restart you comp,
change it back to debug registers later for faster searches when you finished the tut, just use the "MEMORY ACCESS EXEPTIONS" setting for hard to find addesses,
by the way dark byte I tried ce out on a pals 64 bit amd pc and found memory access violations, he had 32 bit windows os, wondered if there were any settings to get round it or is it just hard luck on his part
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Dark Byte Site Admin
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Joined: 09 May 2003 Posts: 25958 Location: The netherlands
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Posted: Mon Sep 25, 2006 1:10 am Post subject: |
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| me wrote: | anyhow you start by freezing the base pointer [45cc18]
then the other addresses with their offsets,
and then make sure you got 5000 in your first found address all frozen then hit the change pointer button,
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Try redownloading ce again and install that. I made a small adjustement so this wrong method will not work anymore (access violation since i'm zeroing and freeing the old pointers on a change pointer, just like a real game)
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ReVoLution Advanced Cheater
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Joined: 24 Sep 2006 Posts: 50
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Posted: Mon Sep 25, 2006 4:18 pm Post subject: |
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dont really understand
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supea Master Cheater
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Joined: 29 Aug 2006 Posts: 323 Location: Finland
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Posted: Tue Sep 26, 2006 8:28 am Post subject: |
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easy, just do it again and again and again if it didnt work. and try find out what READS I found it that way
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