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C++ query.
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MegaForum
Grandmaster Cheater
Reputation: 0

Joined: 20 Aug 2007
Posts: 558
PostPosted: Tue Jan 22, 2008 8:48 pm    Post subject: Reply with quote
Cx wrote:
Haha.
Funny how constructive people can be (and correctly so) about a simple console number addition program.


i completely edited since last night lol. i learned and did it all by myself Very Happy.
heres my new code.
this adds 3numbers and divides by 3 to find average.

Code:

#include <iostream>
#include <cstdlib>
using namespace std;
int main()
{
    int num1, num2, num3, num4;
    num4 = 3;
    cout << "Enter your first number" << endl;
    cin >> num1;
    cout << "Enter your second number" << endl;
    cin >> num2;
    cout << "Enter your third number" << endl;
    cin >> num3;
    cout << "The average of your numbers" << "=" << (num1+num2+num3) /num4 << endl;
    cin.ignore();
    cin.get();
    return 0;
}
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atom0s
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Reputation: 205

Joined: 25 Jan 2006
Posts: 8588
Location: 127.0.0.1
PostPosted: Tue Jan 22, 2008 8:57 pm    Post subject: Reply with quote
Why are you including cstdlib? You don't need it.. And you don't need to declare num4. You can just put / 3 instead. Also, don't use cin.get(), just use cin.sync() with ignore. Like this:

Code:
#include <windows.h>
#include <iostream>

int main()
{
   int iNum1, iNum2, iNum3;

   std::cout << "Enter your first number: ";
   std::cin >> iNum1;

   std::cout << std::endl << "Enter your second number: ";
   std::cin >> iNum2;

   std::cout << std::endl << "Enter your third number: ";
   std::cin >> iNum3;

   std::cout << std::endl << "The average of your numbers is: " << ((iNum1+iNum2+iNum3)/3);

   std::cin.sync();
   std::cin.ignore();
   return ERROR_SUCCESS;
}

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