The value of the address during the first question was 0. The program saves 0 into its memory.
When you goonto your second scan it looks through all the previous 0's looking for any changes that are present during the 2nd scan. If it see's it is still 0(which it would in this case because it changed back BEFORE your 2nd scan occured), You would have to search for an "unchanged" value. _________________
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