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Innovation
Grandmaster Cheater
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Joined: 14 Aug 2008
Posts: 617

PostPosted: Fri Feb 08, 2013 8:42 pm    Post subject:

0x01234567 -> {0x01, 0x23, 0x45, 0x67} -> {0x67, 0x45, 0x23, 0x01} (Reverse Order)

PUSH imm16/32 corresponds to 0x68 (see this for reference).

Putting it together, you have {0x68, 0x67, 0x45, 0x23, 0x01}.

The reason the bytes are reversed is that x86 uses little-endian.
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booingthetroll
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ReviewPosted: Sat Feb 09, 2013 4:09 pm

Thanks.
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