Cheat Engine

[bknight2602]

I guess I wasn't specific enough in the initial post to this idea.

What I want to do is programmically search for an aob "22 41 52 52 45 54 FF FF", the code you have helped me with does this. Then take those results and programmically search for the last 3 (or 4) characters of the found addresses.

Is this possible?

[Dark Byte]

Check http://lua-users.org/wiki/StringLibraryTutorial
I think a combination of string.length and string.sub will do what you wish

Actually, i think string.sub(addressstring, -3) might even return the proper result

Alternatively, convert the address to an integer and do address % 0x1000 and convert back to hex. That will also give the last 3 digits

[bknight2602]

Your vast knowledge wins again, string.sub(addressstring, -3) works perfectly.
Thanks