I guess I wasn't specific enough in the initial post to this idea.
What I want to do is programmically search for an aob "22 41 52 52 45 54 FF FF", the code you have helped me with does this. Then take those results and programmically search for the last 3 (or 4) characters of the found addresses.
Actually, i think string.sub(addressstring, -3) might even return the proper result
Alternatively, convert the address to an integer and do address % 0x1000 and convert back to hex. That will also give the last 3 digits _________________
Do not ask me about online cheats. I don't know any and wont help finding them.
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