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VB.NET Crackme!

 
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sumnewdude
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PostPosted: Thu Feb 28, 2008 8:03 pm    Post subject: VB.NET Crackme! Reply with quote

Hey This is my first Crack me I hope it is decient. If you crack it could you please tell me how you did it? Thanks and Enjoy!

Sorry Ill post the accucal .exe

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Last edited by sumnewdude on Fri Feb 29, 2008 7:34 am; edited 2 times in total
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Pseudo Xero
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PostPosted: Thu Feb 28, 2008 8:43 pm    Post subject: Re: VB.NET Crackme! Reply with quote

sumnewdude wrote:
Hey This is my first Crack me I hope it is decient. If you crack it could you please tell me how you did it? Thanks and Enjoy!

I'm sorry, you shouldn't ever make your crackmes in .NET. All of the code can be decompiled.
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HolyBlah
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PostPosted: Fri Feb 29, 2008 3:36 am    Post subject: Reply with quote

I can't see the crackme download, only the setup...
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sumnewdude
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PostPosted: Fri Feb 29, 2008 6:40 am    Post subject: Re: VB.NET Crackme! Reply with quote

Xenophobe wrote:
sumnewdude wrote:
Hey This is my first Crack me I hope it is decient. If you crack it could you please tell me how you did it? Thanks and Enjoy!

I'm sorry, you shouldn't ever make your crackmes in .NET. All of the code can be decompiled.


What if the password isn't in the code?? Then what?

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atom0s
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PostPosted: Fri Feb 29, 2008 3:43 pm    Post subject: Reply with quote

Code:
        Private Sub Number_Click(ByVal sender As Object, ByVal e As System.EventArgs)
            Dim v_str As String
            Dim v_str1 As String
            Dim v_str2 As String
            v_str1 = Box2.[Text]
            v_str2 = TrytoOpen.[Text]
            If Microsoft.VisualBasic.Strings.Len(v_str1) < 20 Then
                MyProject.Forms.Congratz.Visible = true
                MyProject.Forms.Congratz.Label1.[Text] = "Uhh too short. . ."
            Else
                If Microsoft.VisualBasic.Strings.Len(v_str1) > 19 Then
                    For v_i As Integer = 1 To Microsoft.VisualBasic.Strings.Len(v_str1)
                        v_str = String.Concat(v_str, Conversions.ToString(Microsoft.VisualBasic.Strings.Chr(Microsoft.VisualBasic.Strings.Asc(Microsoft.VisualBasic.Strings.Mid(v_str1, v_i, 1)) + 7)))
                    Next v_i
                    If Operators.CompareString(v_str2, v_str, false) = 0 Then
                        MyProject.Forms.TryAgain.Visible = true
                        Panel1.Visible = true
                        Label1.Visible = true
                    Else
                        If (Operators.CompareString(v_str1, "Hello mate!", false) = 0) AndAlso (Operators.CompareString(v_str2, "How are you?", false) = 0) Then
                            MyProject.Forms.You_Win.Visible = true
                        Else
                            MyProject.Forms.Congratz.Visible = true
                        End If
                    End If
                End If
            End If
        End Sub






Suggestions:
Don't code in VB.NET for secure style applications.

Tool To Use
9Rays.Spices.Net Decompiler.

Password(s)
Looking at the code above, you can see it splits the string entered into line 1 letter by letter then adds 7 to the characters numeric value. It enforces 20 characters or longer and then you must match the 2nd box to the above box +7 on each letter.

A quick example:
1 = 8

So a quick password solution:
Box 1: 11111111111111111111
Box 2: 88888888888888888888

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sumnewdude
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PostPosted: Fri Feb 29, 2008 4:02 pm    Post subject: Reply with quote

Wiccaan wrote:


Suggestions:
Don't code in VB.NET for secure style applications.

Tool To Use
9Rays.Spices.Net Decompiler.

Password(s)
Looking at the code above, you can see it splits the string entered into line 1 letter by letter then adds 7 to the characters numeric value. It enforces 20 characters or longer and then you must match the 2nd box to the above box +7 on each letter.

A quick example:
1 = 8

So a quick password solution:
Box 1: 11111111111111111111
Box 2: 88888888888888888888

Cool . . . I think I found your decompiler that you used but I can't seem to get it to work. .. Sad

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